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2 years ago

Which graph shows the solution to the equation 4^x– 3 = 8?

Mathematics

1 answer:

In-s [12.5K]2 years ago

6 0

Answer:

Answer C.

Step-by-step explanation:

We can quickly notice that Answer C is the correct answer by looking at the right-hand side of the equation. The number '8' means that a horizontal line at y=8 will be graphed along with the exponential function.

Answer C is the only graph with a line at y=8.

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1 2 3 4 5

mylen [45]

Answer:

B) 8x10^(-8)

Hope it helps

7 0

2 years ago

If anyone Answer this question with POLITICALLY CORRECT answer I'll give you 25+ Points

Tresset [83]

Answer:

$\sqrt[4]{x^5}$

Step-by-step explanation:

A fraction exponent converts into a radical. The denominator is the index of the radical (farthest left number) and the numerator is the exponent of the base inside (the farthest right number). The base of the fraction exponent is the base number in green. To write this expression, simply the exponents into one exponent and one base.

$x^{\frac{3}{4}}x^{\frac{1}{2} } =x^{\frac{3}{4}}x^{\frac{2}{4} } =x^{\frac{3+2}{4}} =x^{\frac{5}{4}}$

Now convert to the radical.

$x^{\frac{5}{4}} = \sqrt[4]{x^5}$

8 0

3 years ago

What is the midpoint of AB?

dem82 [27]

It looks like Point G is correct

3 0

3 years ago

Kit bought a soft drink and a sandwich for $9.00. What was the price of each if the sandwich cost 3.5 times much as the soft dri

astra-53 [7]

Let the cost of the soft drink = C then the price of the sandwich was 3.5 times as much = 3.5C

And

C + 3.5C = Total Cost

C + 3.5C = 9

4.5C = 9 divide both sides by 4.5

C = 9/4.5 = $2.00 for the soft drink

And 3.5C = 3.5(2.00) = $7.00 cost of the sandwich

8 0

3 years ago

Read 2 more answers

A 140 kg camera is suspended by two wires over a 40 metre wide football field to get shots of the action from above. At one poin

Katen [24]

Answer:

Please red the answer below

Step-by-step explanation:

In order to determine the length of each cable you use the Newton second law for each component of the forces involved in the situation.

For the x component you have:

$T_1cos\theta_1-T_2cos\theta_2=0$ (1)

T1: tension of the first cable = 1500N

T2: tension of the second cable = 800N

θ1: angle between the horizontal and the first cable

θ2: angle between the horizontal and the first cable

For the y component you have:

$T_1sin\theta_1+T_2sin\theta_2-W=0$ (2)

W: weight of the camera = Mg = (140kg)(9.8m/s^2) = 1372N

You can squared both equations (1) and (2) and the sum the two equations:

$T_1^2cos^2\theta_1=T_2^2cos^2\theta_2\\\\T_1^2sin^2\theta_1=T_2^2sin^2\theta_2-2WT_2sin\theta_2+W^2$

Then, you sum the equations:

$T_1^2(cos^2\theta_1+sin^2\theta_1)=T_2^2(sin^2\theta_2+cos^2\theta_2)-2Wsin\theta_2+W^2$ (3)

Next, you use the following identity:

$sin^2\theta+cos^2\theta=1$

and you obtain in the equation (3):

$T_1^2=T_2^2-2WT_2sin\theta_2+W^2\\\\sin\theta_2=\frac{T_2^2-T_1^2+W^2}{2WT_2}=\frac{(800N)^2-(1500)^2+(1372N)^2}{2(800N)(1372N)}=0.066\\\\\theta_2=sin^{-1}0.066=27.23\°$

With this values you can calculate the value of the another angle, by using the equation (1):

$\theta_1=cos^{-1}(\frac{T_2cos(27.23\°)}{T_1})=cos^{-1}(\frac{(800N)(cos27.23\°)}{1500N})\\\\\theta_1=61.69\°$

Now, you can calculate the length of each cable by using the information about the width of the football field. You use the following trigonometric relation:

$l_1cos\theta_1=40-d\\\\l_2cos\theta_2=d\\\\$

d: distance to the right side of the field

By using the cosine law you can fins a system of equation and then you can calculate the values of l1 and l2.

3 0

2 years ago