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Yuki888 [10]
3 years ago
6

A student needed to prepare 500mL of 1X TAE buffer to run a QC gel. The stock solution in the lab is 5X TAE. What volumes of sto

ck TAE and water are needed to prepare the 1X working TAE buffer?
Mathematics
2 answers:
Xelga [282]3 years ago
3 0

Answer:

you need 100ml of 5X TAE and 400ml of water.

Step-by-step explanation:

You need to use a rule of three:

C_1V_1=C_2V_2

where:

\left \{ {{C_1= 5X} \atop {C_2=1X}} \right.

and

\left \{ {{V_1 = V_{TAE}} \atop {V_2=500ml}} \right.

Therefore:

V_{TAE} = \frac{V_2*C_2}{C_1}

V_{TAE} = 100ml

Then just rest the TAE volume to the final Volume and you get the amount of water that you need to reduce the concentration.

tankabanditka [31]3 years ago
3 0

Answer:

You need 750 ml deionized water and 57.1 ml glacial acid and 100 ml of 0.5 M  EDTA

Step-by-step explanation:

The stock solution is made by making a concentrated solution of TAE by weighing out 242 grams of Tris base. This is then dissolved in approximately 750 milliliters of deionized water. After that, 57.1 ml of glacial acid are added to the 100 l of 0.5 M EDTA. After that, the final volume is adjusted to 1 liter. This will be the stock solution of the buffer solution.

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Given the Arithmetic series A 1 + A 2 + A 3 + A 4 A1+A2+A3+A4 14 + 18 + 22 + 26 + . . . + 86 What is the value of sum?
postnew [5]

Answer:

950

Step-by-step explanation:

The common difference is 4, so the general term can be written:

... an = 14 + 4(n -1)

The value of n for the last term is ...

... 86 = 14 + 4(n -1) . . . . . the computation for the last term, 86

... 72 = 4(n -1) . . . . . . . . . subtract 14

... 18 = n -1 . . . . . . . . . . . divide by 4

... 19 = n . . . . . . . . . . . . . add 1

Your series has 19 terms. The first term is 14 and the last is 86, so the average term is (14+86)/2 = 50. Since there are 19 terms, the sum of them is ...

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7 0
3 years ago
Trisha packs x boxes with 12 bottles in each box. The total number of bottles she packs is 216. Which equation and solution repr
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Answer:

Number of boxes Trisha pack = 18 boxes

Step-by-step explanation:

Given:

Number of boxes Trisha pack = X

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Find:

Number of boxes Trisha pack

Computation:

Total number of bottle = Number of boxes Trisha pack x Number of bottles in each box

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-4x - 6 = 10

To solve the equation, you will have to isolate the x. Because of the equal sign, what you do to one side, you do to the other.

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Do the opposite of PEMDAS. First add 6 to both sides

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