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Stolb23 [73]
2 years ago
5

In frequency curve the points are joined by bits of a straight line. True/False​

Mathematics
1 answer:
pashok25 [27]2 years ago
7 0
False. The frequency curve for a distribution can be obtained by drawing a smooth and free hand curve through the midpoints of the upper sides of the rectangles forming the histogram.
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The result of subtracting 2 from its opposite is
belka [17]
It’s four because you subtract 2 minus negative 2
4 0
3 years ago
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What is the product of −3/11 and <br> −2/15?
Dafna11 [192]
Multiply -3/11 and -2/15 straight across

-3(-2) = 6
11(15) = 165

6/165 is your product, or 0.036 (rounded)


hope this helps
5 0
3 years ago
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If a basketball has a volume of 12,114.7 cm3, what is the distance across of a basketball
kirza4 [7]


All we need to do is start with the volume formula. Then, input the volume and solve the equation for the radius. And double it to get the diameter.

V = (4/3)pi(r^3)
12114.7 = (4/3)pi(r^3)  Divide both sides by (4/3) and pi
2893.64 = r^3              Take the cube root of both sides
14.25 = r

So the diameter is about 28.5 cm (14.25 x 2 = 28.5)
4 0
3 years ago
Which expression equals 6x − 5y + 2 − 8x + 3( y + 5)? A) 3x − 2y + 17 B) −3x + 2y + 17 C) −2x − 2y + 17 D) −2x − 2y − 17
inysia [295]

Answer:

<u>C) −2x − 2y + 17</u>

Step-by-step explanation (PEMDAS):

First, we do <u>3 (y + 5)</u> because of the parenthesis:

6x − 5y + 2 − 8x + 3y + 15

Since there are no exponents, multiplication ,or division, we will add and subtract. But we have to make sure we <u>combine like terms</u>. X with X's, Y with Y's and constants with constants. And ALWAYS go from left to right

6x − 5y + 2 − 8x + 3y + 15

<u>−2x</u> − 5y + 2 + 3y + 15

−2x <u>− 2y</u> + 2 + 15

<em>−2x − 2y</em><em> </em><em>+ </em><em><u>17</u></em><em>.</em>

8 0
3 years ago
Which or the following is the radical expression of 4d3/8
stira [4]

Answer:

\boxed{4 \sqrt[8]{ {d}^{3} } }

Step-by-step explanation:

=  > 4 {d}^{ \frac{3}{8} }   \\  \\ =   > 4({d}^{3 \times  \frac{1}{8} }) \\  \\  =  > 4( {d}^{3}  \times   {d}^{ \frac{1}{8} } ) \\  \\  =  > 4( {d}^{3}  \times  \sqrt[8]{d} ) \\  \\  =  > 4  \sqrt[8]{ {d}^{3} }

3 0
3 years ago
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