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solmaris [256]
4 years ago
6

What is 1 3\4 + 2 2/3

Mathematics
1 answer:
cricket20 [7]4 years ago
3 0

Hello!

<em><u>Answer:</u></em>

<em><u>4 5/12</u></em>

<em><u>*The answer must have a whole number and a fraction.*</u></em>

Step-by-step explanation:

Lesson: Adding Fractions

First, you add by the whole number.

1+2=3

Then you combine by the fraction or number.

\frac{3}{4}+\frac{2}{3}=\frac{17}{12}

3+\frac{17}{12}

Next, you convert improper fraction into the mixed numbers.

\frac{17}{12}=1\frac{5}{12}

3+1\frac{5}{12}

And finally, add by the numbers.

3+1=4

Final answer: → 4\frac{5}{12}

Hope this helps!

Thanks!

Have a great day!

-Charlie

:)

:D

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4)In order to set rates, an insurance company is trying to estimate the number of sick daysthat full time workers at an auto rep
bagirrra123 [75]

Answer:

A sample of 18 is required.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.92}{2} = 0.04

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.04 = 0.96, so Z = 1.88.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

A previous study indicated that the standard deviation was 2.2 days.

This means that \sigma = 2.2

How large a sample must be selected if the company wants to be 92% confident that the true mean differs from the sample mean by no more than 1 day?

This is n for which M = 1. So

M = z\frac{\sigma}{\sqrt{n}}

1 = 1.88\frac{2.2}{\sqrt{n}}

\sqrt{n} = 1.88*2.2

(\sqrt{n})^2 = (1.88*2.2)^2

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Rounding up:

A sample of 18 is required.

3 0
3 years ago
What are the vertex, axis of symmetry, domain and range of the function:
DiKsa [7]
Y=(-x*x)-4x+3
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Answers:
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3 0
3 years ago
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answer= -3 1/2
8 0
3 years ago
An article in Fire Technology investigated two different foam-expanding agents that can be used in the nozzles of firefighting s
UNO [17]

Answer:

Step-by-step explanation:

Hello!

The objective of this experiment is to test if two different foam-expanding agents have the same foam expansion capacity

Sample 1 (aqueous film forming foam)

n₁= 5

X[bar]₁= 4.7

S₁= 0.6

Sample 2 (alcohol-type concentrates )

n₂= 5

X[bar]₂= 6.8

S₂= 0.8

Both variables have a normal distribution and σ₁²= σ₂²= σ²= ?

The statistic to use to make the estimation and the hypothesis test is the t-statistic for independent samples.:

t= \frac{(X[bar]_1 - X[bar]_2) - (mu_1 - mu_2)}{Sa*\sqrt{\frac{1}{n_1} + \frac{1}{n_2 } } }

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(X[bar]_1 - X[bar]_2) ± t_{n_1 + n_2 - 2}*Sa* \sqrt{\frac{1}{n_1}+\frac{1}{n_2} }

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[-4.78; 0.38]

With a 95% confidence level you expect that the interval [-4.78; 0.38] will contain the population mean of the expansion capacity of both agents.

b.

The hypothesis is:

H₀: μ₁ - μ₂= 0

H₁: μ₁ - μ₂≠ 0

α: 0.05

The interval contains the cero, so the decision is to reject the null hypothesis.

<u>Complete question</u>

a. Find a 95% confidence interval on the difference in mean foam expansion of these two agents.

b. Based on the confidence interval, is there evidence to support the claim that there is no difference in mean foam expansion of these two agents?

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- Hope I helped :)
- PeaceLoveHappiness
6 0
3 years ago
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