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solmaris [256]
3 years ago
6

What is 1 3\4 + 2 2/3

Mathematics
1 answer:
cricket20 [7]3 years ago
3 0

Hello!

<em><u>Answer:</u></em>

<em><u>4 5/12</u></em>

<em><u>*The answer must have a whole number and a fraction.*</u></em>

Step-by-step explanation:

Lesson: Adding Fractions

First, you add by the whole number.

1+2=3

Then you combine by the fraction or number.

\frac{3}{4}+\frac{2}{3}=\frac{17}{12}

3+\frac{17}{12}

Next, you convert improper fraction into the mixed numbers.

\frac{17}{12}=1\frac{5}{12}

3+1\frac{5}{12}

And finally, add by the numbers.

3+1=4

Final answer: → 4\frac{5}{12}

Hope this helps!

Thanks!

Have a great day!

-Charlie

:)

:D

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During an Apollo moon landing, reflecting panels were placed on the moon. This allowed Earth-based astronomers to shoot laser be
rusak2 [61]

Answer:

The distance between the astronomers and the moon was 7.56*10^{8] meters.

Step-by-step explanation:

We have that the speed is the distance divided by the time, so:

v = \frac{d}{t}

In this problem, we have that:

The reflected laser beam was observed by the astronomers 2.52 s after the laser pulse was sent. This means that t = 2.52.

If the speed of light is 3.00 times 10^8 m/s, what was the distance between the astronomers and the moon?

We have that v = 3*10^{8}m/s.

We have to find d. So:

v = \frac{d}{t}

d = vt

d = 3*10^{8}*2.52

7.56*10^{8]

The distance between the astronomers and the moon was 7.56*10^{8] meters.

7 0
3 years ago
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Natali5045456 [20]

Answer:

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6 0
2 years ago
Which is a equivalent to 80 1/4x
elena55 [62]
Since you did not provide options for what 80\frac{1}{4}x could be equivalent to,, it is near to impossible to answer this question fully. I will simplify 80\frac{1}{4}x for you and then when you can provide the options for me,, I could help you find the answer if you need it. 
To simplify this you must reduce the numbers with 4 in order to find your final answer.
20x.
This means that the correct answer to your question is 20x.
Let me know if you have any further questions.
:)
7 0
3 years ago
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The key to this question is
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ValentinkaMS [17]
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