Alright so I'm coming up with this on the fly; you have the first six letters (a,b,c,d,e,f) and 0-9 and your ten numbers. calculate the amount of possible combinations for the letters by simply writing them down.
ab, ac, ad, ae, a f- five
bc, bd , be, bf- four
cd, ce, cf- three
de, df- two
ef,- one.
adding these all together gets a total of 15 for the letters. now the numbers
01, 02, 03, 04, 05, 06, 07, 08, 09- nine
12, 13, 14, 15, 16, 17, 18, 19- eight
23, 24, 25, 26, 27, 28, 29- seven
34, 35, 36, 37, 38, 39- six
45, 46, 47, 48, 49- five
56, 57, 58, 59- four
67, 68, 69- three
78, 79- two
89- one
added together with a total of 45 combinations.
alright so, 45 different number combinations and 15 letter combinations. multiplying 15 by 45 should tell you the total possible combinations for a two letter and two number serial-number
F(x) +g(x)
= (5x -2) +(2x +1)
= 7x -1 . . . . . . . . . . . . matching selection A
Terms are the different things being added/subtracted. There are 5 terms.
Answer:
Step-by-step explanation:
A reasonable estimate of the amount Donna is left with each week after the money is deducted: $980. 1404*.19=266.76 ; 1404*.12=168.48 ; 1404-266.76-168.48=968.76 or estimated as $980.
It should be noted that the relationship is not linear based on the information illustrated as the difference between the numbers aren't the same.
<h3>How to illustrate the information?</h3>
It should be noted that an equation is simply used to illustrate and express the relationship between the variables.
It should be noted that for the relationship to be linear, it's essential that they've the same relationship between them.
When x = 1, y = 4.5. The
When x = 2, y = 6.5
When x = 3, y = 8.5
When x = 4 y = 11.5
It should be noted that there's a difference of 2 at first but between 3 and 4, there is. a difference of 3.
Therefore, the relationship is not linear.
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