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2 years ago

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Suppose three moons A, B, and C orbit 100,000 kilometers above the surface of a planet. Suppose m ZABC = 90°, and the planet is

20,000 kilometers in diameter. Draw a diagram of the situation. How far is moon A from moon C?

2 answers:

alexira [117]2 years ago

7 0

Answer:

Step-by-step explanation:

AC is 220000km according to the drawing:

Vesna [10]2 years ago

3 0

Answer:

Step-by-step explanation:

Please see diagram attached.

Moon A and C are 100,000km + 10,000 = 110,000km from center of planet.

So they are 110,000 + 110,000 = 220,000km apart.

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lesya [120]

The simplest path from (0, 0, 0) to (1, 1, 1) is a straight line, denoted $C$ , which we can parameterize by the vector-valued function,

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for $0\le t\le1$ , which has differential

$\mathrm d\mathbf r=-(\mathbf i+\mathbf j+\mathbf k)\,\mathrm dt$

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Complete the square in the quadratic term of the integrand: $t^2-2t+2=(t-1)^2+1=(1-t)^2+1$ , then in the integral we substitute $u=1-t$ :

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Make another substitution of $v=u^2$ :

$\displaystyle=-\int_{v=0}^{v=1}e^v(v+1)\,\mathrm dv$

Integrate by parts, taking

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So, we have by the fundamental theorem of calculus that

$\displaystyle\int_C\nabla f(x,y,z)\cdot\mathrm d\mathbf r=f(1,1,1)-f(0,0,0)$

$\implies-e=f(1,1,1)-2$

$\implies f(1,1,1)=2-e$

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