Suppose three moons A, B, and C orbit 100,000 kilometers above the surface of a planet. Suppose m ZABC = 90°, and the planet is
2 answers:
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Using proportions, it is found that:
- Peter is walking at a rate of 3 km/h.
- MJ is biking at a rate of 9 km/h.
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- Peter is walking at a rate of x km/h.
- MJ is biking 6 km/h faster than Peter, thus 6 + x km/h.
- Opposite directions, thus, their distance increases at a rate of (6 + 2x) km each hour, as
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6 + 2x km each hour, 18 km after 1.5 hours, thus, the rule of three is:
1h - (6 + 2x) km
1.5h - 18 km
Applying cross multiplication:
Then:
- Peter is walking at a rate of 3 km/h.
- MJ is biking at a rate of 9 km/h.
A similar problem is given at brainly.com/question/24112433