
<h3><u>A</u><u>N</u><u>S</u><u>W</u><u>E</u><u>R</u><u>:</u></h3><h3>V = 1,800 cm</h3><h3><u>S</u><u>O</u><u>L</u><u>U</u><u>T</u><u>I</u><u>O</u><u>N</u><u>:</u></h3><h3>V = l × w × h</h3><h3>V = 18 × 10 × 10</h3><h3>

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<h3>----------<u>❥︎</u><u>X</u><u>x</u><u>Y</u><u>u</u><u>n</u><u>a</u><u>K</u><u>o</u><u>h</u><u>a</u><u>r</u><u>u</u><u>C</u><u>h</u><u>a</u><u>n</u><u>x</u><u>X</u></h3>
Answer: Wall 1 & 2 : 26 ft by 9 ft
Wall 3 : 18 ft by 9 ft
Area 1 : 26 ft x 9 ft = 234 ft²
Area 2 : 26 ft x 9 ft = 234 ft²
Area 3 : 18 ft x 9 ft = 162 ft²
Total Area : 234 ft² + 234 ft² + 162 ft² = 630 ft²
1 Gallon = 250 ft²
630 ft² ÷ 250 ft² per gallon = 2.52 gallons
<u>3x³y - 14x²y - 7xy</u> = <u>3</u>x - 2 - <u>1</u>
7x²y 7 x
Answer:
we will fail to reject the null hypothesis and conclude that the return rate is less than 20%.
Step-by-step explanation:
We are given;
Sample size;n = 6970
Success rate;X = 1334/6970 = 0.1914
Now, we want to test the claim that the return rate is less than p = 0.2, hence the null and alternative hypothesis are respectively;
H0: μ < 0.2
Ha: μ ≥ 0.2
The standard deviation formula is;
σ = √(x(1 - x)/n)
σ = √(0.1914(1 - 0.1914)/6970)
σ = 0.004712
Now for the test statistic, formula is;
z = (x - μ)/σ
z = (0.1914 - 0.2)/0.004712
z = -1.825
From the a-distribution table attached, we have a value of 0.03362.
This p-value gotten from the z-table is more than the significance value of 0.01. Thus, we will fail to reject the null hypothesis and conclude that the return rate is less than 20%.
Answer:
x ≤ 16 and x ≥ -2
Step-by-step explanation:
3 |x-7| ≤ 27
• divide both sides by 3:
|x-7| ≤ 9
• first assume the positive case of the absolute value:
x-7 ≤ 9
• add 7 to both sides:
x ≤ 16
• Now, go back to the absolute value and assume the negative case.
-(x-7) ≤ 9
-x+7 ≤ 9
• subtract 7 from both sides:
-x ≤ 2
• divide each side by -1 and flip the inequality sign:
x ≥ -2