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melisa1 [442]
3 years ago
12

I need help. I have been stuck on this for an hour now.​

Mathematics
2 answers:
topjm [15]3 years ago
8 0

Answer:

The one about the beetles

Step-by-step explanation:

Margarita [4]3 years ago
5 0

I think the answer is

A beetle population first recorded at 10,000, has been declining over the last few years due to a pesticide. Each year, there are half as many beetles as they year before.

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The weight of football players is normally distributed with a mean of 200 pounds and a standard deviation of 25 pounds,What perc
soldier1979 [14.2K]

Answer:

57.62% of players weigh between 180 and 220 pounds

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 200, \sigma = 25

What percent of players weigh between 180 and 220 pounds

We have to find the pvalue of Z when X = 220 subtracted by the pvalue of Z when X = 180.

X = 220

Z = \frac{X - \mu}{\sigma}

Z = \frac{220 - 200}{25}

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4 0
3 years ago
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