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valina [46]
3 years ago
9

Solve the problem:

Mathematics
1 answer:
stepan [7]3 years ago
5 0

volume of the box is 675 cubic inches

A machine produces open boxes using square sheets of plastic.

It is a square sheet so length and width are same

Lets assume length as x so width is also x

The machine cuts equal-sized squares measuring 3 inches on a side from each corner of the sheet.

After turning up the sides the height of the box becomes 3 inches

We know the volume of a box formula

Volume = Length * width * height

We know length is  x , width is x  and height = 3

So V = x * x * 3

Given volume = 675 cubic inches

675 = x * x * 3

675 = x^2* 3

Divide by 3 on both sides

225 = x^2

Now we take square root on both sides

x = 15

the length of one side of the open box is 15 inches.



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Me. Gonzalez packs 45 boxes with limes. Each box holds 100 limes . How many limes can ms. Gonzalez pack into these boxes
Monica [59]

Answer:

4,500

Step-by-step explanation:

To find the total number of limes, you need to multiply the group number (45 boxes) by the amount each can hold (100 limes).

45 x 100 = 4500 limes

3 0
2 years ago
Read 2 more answers
Plz help me with this
Nitella [24]

Answer: C) y ≥ 3x - 2;  y\leq \dfrac{1}{2}x+3

<u>Step-by-step explanation:</u>

Blue line:

y-intercept (b) = -2

slope (m) is 3 up, 1 right = 3

shading is above

⇒ y ≥ 3x - 2

Yellow line:

y-intercept (b) = 3

slope (m) is 1 up, 2 right = \dfrac{1}{2}

shading is below

\implies \bold{y\leq \dfrac{1}{2}x+3}

8 0
3 years ago
What are the solutions to the equation
frosja888 [35]

Answer:

C.

x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i and x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i

Step-by-step explanation:

You have the quadratic function 2x^2-x+1=0 to find the solutions for this equation we are going to use Bhaskara's Formula.

For the quadratic functions ax^2+bx+c=0 with a\neq 0 the Bhaskara's Formula is:

x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}

x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}

It usually has two solutions.

Then we have  2x^2-x+1=0  where a=2, b=-1 and c=1. Applying the formula:

x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}\\\\x_1=\frac{-(-1)+\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_1=\frac{1+\sqrt{1-8} }{4}\\\\x_1=\frac{1+\sqrt{-7} }{4}\\\\x_1=\frac{1+\sqrt{(-1).7} }{4}\\x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}

Observation: \sqrt{-1}=i

x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}\\\\x_1=\frac{1+i.\sqrt{7}}{4}\\\\x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i

And,

x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}\\\\x_2=\frac{-(-1)-\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_2=\frac{1-i.\sqrt{7} }{4}\\\\x_2=\frac{1}{4}-(\frac{\sqrt{7}}{4})i

Then the correct answer is option C.

x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i and x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i

3 0
2 years ago
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