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Aleks04 [339]
3 years ago
10

Which equation does the graph below represent?

Mathematics
1 answer:
Anna [14]3 years ago
4 0

Answer:

a

Step-by-step explanation:

i think its a

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Find the area of the shaded region
kogti [31]

Answer:

  7. 183 in^2

  8. 192.42 m^2

  9. 239.4 ft^2

Step-by-step explanation:

7. The figure seems most easily seen as a trapezoid with a triangle removed. The trapezoid has bases of 26 and 14, and a height of 15. So, its area is ...

  A = (1/2)(b1 +b2)(h) = (1/2)(26+14)(15) = 300 . . . . . . square inches

The triangle has a base of 26 and a height of 9, so an area of ...

  A = (1/2)bh = (1/2)(26)(9) = 117 . . . . . . square inches

Then the shaded area is ...

  300 in^2 -117 in^2 = 183 in^2

__

8. The area of the donut can be found different ways. One way is to multiply the width of the shaded area (3.5 m) by the circumference of its centerline.

The centerline diameter is 21 m - 3.5 m = 17.5 m, so the circumference of that circle is ...

  C = πd = π(17.5 m) = 17.5π m

Then the area of the shaded part is ...

  (3.5 m)(17.5π m) = 61.25π m^2 ≈ 192.42 m^2

__

9. As in problem 7, this can be treated as a parallelogram less a triangle. Here, we need to do a little work to find the area of the triangle.

The triangle of interest is a right triangle with hypotenuse 23.8 ft and one leg 21 ft. The Pythagorean theorem can be used to find the other leg:

  h = √(23.8^2 -21^2) = √125.44 = 11.2

Then the area of the triangle is ...

  A = (1/2)bh = (1/2)(21)(11.2) = 117.6 . . . ft^2

The area of the parallelogram (including the triangle) is ...

  A = bh = (23.8 ft)(15 ft) = 357 ft^2

So, the shaded area is the difference ...

  357 ft^2 -117.6 ft^2 = 239.4 ft^2

_____

<em>Comment on significant digits</em>

The area in problem 8 may be considered to be 192.325 m^2 if you are required to use 3.14 as the value for pi. Since that value is only good to 3 significant digits, it is quite pointless to report the answer to 6 significant digits when using that value. It is quite reasonable to use 192 m^2 for the answer, especially if you're required to round to whole numbers.

8 0
3 years ago
What is a straight path that has a beginning but not an ending
ohaa [14]
The answer is a Ray.
7 0
3 years ago
Please help me! Im so confused. If you could explain, too that would be great!!! &lt;3
Zielflug [23.3K]

Answer:

the base length is 8 units

Step-by-step explanation:

You can use pythagorean theorem to solve this

8 0
1 year ago
Find the slope of the line that passes through (8, 4) and (5, 2).
Troyanec [42]

If u you do the slope formula...(m=y2-y1/x2-x1)

2-4/5-8
-2/-3=2/3
Therefore the slope would be 2/3
Btw can u plz mark this answer the brainliest
8 0
3 years ago
Please help me with this I’m confused please explain
Maksim231197 [3]

Answer:

25. If you look at angle B from the first figure you see a square that indicates a 90 degrees angle, thus the figure shown is a right triangle. You can also see that angle C is said to have 60 degrees. a right triangle has a total angle of 180 degrees. so, 180 - 90 - 60 = 30 degrees. Therefore, angle A is 30 degrees.

27. Now you want the measure of the hypotenuse, and you know this a right triangle. so, simply use the law of sines to find the measure of AC :

4cm/sin(60) = AC/Sin90

AC = 4.62 cm

29. angle z is in the other figure and same stuff, just substract the angles, you have 90 degrees and 30 degrees... 180 - 90 - 30 = 60 degrees

31. Angle Y = 90 degrees

this value is already given, it's the little square that indicates a 90 degrees angle.

26. 5 cm

28. 90 degrees

30. You already found AC, use the pythagorean theorem. sqrt((4.62)^2 - 4^2) = 2.31 cm

32. use pythagoras again, square root(5^2 - 3^2) = 4

So as you can see all the measurements are the same because if you see at the very top of your figures it says ABC = XYZ which means pretty much that they have the same values (notice that there is a little something added to the = sign, watch out for that because that's what indicates that two figures are equal in terms of angles and measures.

7 0
3 years ago
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