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neonofarm [45]
3 years ago
11

Describe the given set with a single equation or with a pair of equations. The plane through the point (7 comma 6 comma negative

3 )(7,6,−3) parallel to___________.a. the ​xy-planeb. the yz​-planec. the​ xz-plane
Mathematics
1 answer:
devlian [24]3 years ago
8 0

Answer:

(a) Along the xy-plane,

7x + 6y = 0

(b) Along the yz-plan,

2y - 3z = 0

(c) Along the xz-plane,

7x - 3z = 0

Step-by-step explanation:

To describe the given set.

Given the plane (7, 6, -3),

We have the equation as

7x + 6y - 3z = 0

(a) Along the xy-plane, z = 0, and we have

7x + 6y = 0

(b) Along the yz-plan, x = 0, and we have

6y - 3z = 0

Or

2y - 3z = 0

(c) Along the xz-plane, y = 0, and we have

7x - 3z = 0

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A vender bought an earphone for $1378 and she sold it in order to make a profit of 17. 5% calculate the profit made in cash and
Inessa [10]

The profit he made from selling his hearing aids at a profit of 17% is $234.26.

<h3>How to calculate the profit obtained?</h3>

To calculate the profit obtained, we must calculate how much money is equal to 17% of $1,378.

  • $1,378 ÷ 100 = $13.78
  • $13.78 × 17 = $234.26

Based on the above, 17% of $1,378 equals $234.26. On the other hand, to calculate the final sale price of the earphone, we add the initial value plus the value of the profit.

$1,378 + $234.26 = $1,612.26

Learn more about profit in: brainly.com/question/15293328

8 0
2 years ago
It ok Khalid 90 minutes to complete 40 task. Which answer choice is an equivalent rate.
solniwko [45]

Answer:

its d

Step-by-step explanation:

he did one task in 2.25 mins so multiply by 10

5 0
2 years ago
Need help with these 2 problems will give brainliest answer and worth 30 points!!
Elena L [17]
Question 1.
Step 1. Add the total cost of purchasing the luxury items:
TotalCost=35.95+34.65+15.30+6.99+42.96=135.85
You will spend $135.85 purchasing the luxury items.

Step 2. Add the total cost of purchasing the name brand items:
TotalCost=19.95+15.98+9.40+4.99+29.75=80.07
You will spend $80.07 purchasing the name brand items.

Step 3. Subtract the total cost of purchasing the name brand items from the total cost of purchasing the luxury items:
135.85-80.07=55.78

Answer to the original question:
We can conclude that you will spend $55.78 more by purchasing the luxury items.

Question 2:

Part 1. 
To find the how many months will take to pay the card debt, we are going to use the credit card equation: N=- \frac{1}{30}* \frac{ln(1+ \frac{b}{p}*(1+ \frac{r}{365})^{30}))  }{ln(1+ \frac{r}{365}) }
where
N is the months to pay the card
b is the balance 
p is the monthly payment 
r is the interest rate in decimal form 

We know from our problem that the balance of the credit card is $1,367.90 and the monthly payment is $400.00, so b=1367.90 and p=400. To find convert the interest rate to decimal form, we are going to divide the rate by 100% 
r= \frac{9.5}{100}=0.095.
Now that we have all we need, lets replace the values in our credit card equation: 
N=- \frac{1}{30}* \frac{ln(1+ \frac{b}{p}*(1+ \frac{r}{365})^{30})) }{ln(1+ \frac{r}{365}) }
N=- \frac{1}{30}* \frac{ln(1+ \frac{1367.90}{400}*(1+ \frac{0.095}{365})^{30})) }{ln(1+ \frac{0.095}{365}) }
N=3.4799

It will take you 3.5 months according to our calculation, but since you pay $400 each month on the due date, we can conclude that it will take you 4 months to pay off the card.

Part 2. To calculate the total amount paid including the interest, we just need to multiply the monthly payment by the number of payments.
We know from our problem that the monthly payment is $400. We also know from our previous calculations that the number of payments is 4, so lets multiply both quantities:
400*4=1600

We can conclude that the total amount paid including interest is $1,600


5 0
3 years ago
we bought a dozen of apples. we used half of them to make apple juice. my dad ate two more.how many left?
Aleks [24]
4 is the answer for that one
3 0
2 years ago
Hey...
CaHeK987 [17]

Answer:

375000000

Step-by-step explanation:

~Kandy~
Hope this helped!
Brainliest please!

5 0
2 years ago
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