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2 years ago

Which graph represents the solution set of the system of inequalities?

Mathematics

1 answer:

RideAnS [48]2 years ago

5 0

Answer:

i think it is top right one and good luck with K12

Step-by-step explanation:

pls give brainliest

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Please help me ASAP!!

Sati [7]

The answer is D, i.e. the system was solved via elimination

If you multiply the first equation by 5, the system becomes

$\left \{ {{-5x-10y=35} \atop {5x-6y=-3}} \right.$

If you sum the two equations, you get

$-16y = 32$

And so if you substitute the second equation of system A with this new equation, you'll get system B.

3 0

2 years ago

What's 7% of 24,678?

Anuta_ua [19.1K]

U just do 24,678 * .07 to get <span>1727.46</span>

4 0

3 years ago

for any positive integer n, the sum of the first n positive integers equals n(n 1)/2. what is the sum of all the even integers b

marusya05 [52]

The sum of all the even integers between 99 and 301 is 20200

To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.

In this case, the first even integer will be 100 and the last even integer will be 300.

nth term of the AP = first term + (n-1) x common difference

⇒ 300 = 100 + (n-1) x 2

Therefore, n = (200 + 2 )/2 = 101

That is, there are 101 even integers between 99 and 301.

Sum of the 'n' terms in an AP = n/2 ( first term + last term)

= 101/2 (300+100)

= 20200

Thus sum of all the even integers between 99 and 301 = 20200

Learn more about arithmetic progressions at brainly.com/question/24592110

#SPJ4

7 0

1 year ago

Will give brainliest!

hram777 [196]

Answer:

Step-by-step explanation:

multiply 0.83 by 0.06 = 0.0498

multiply 0.17 by 0.52 and add that to the first one

which gives you the prob of winning of 0.1382

6 0

3 years ago

The number of transistors per IC in 1972 seems to be about 4,000 (a rough estimate by eye). Using this estimate and Moore's Law,

spayn [35]

Answer:

The prediction for the number of transistor per IC in 1992 is of 4,194,304,000

Step-by-step explanation:

Moore's law:

Moore's law states that the number of transistors per IC doubles every year.

Format of the function:

Following Moore's law, t years after our initial estimative, the number of transistors per IC will be given by:

$N(t) = N(0)*2^t$

In which N(0) is the initial estimate.

The number of transistors per IC in 1972 seems to be about 4,000 (a rough estimate by eye).

This means that $N(0) = 4000$

$N(t) = 4000*2^t$

What would you predict the number of transistors per IC to be 20 years later, in 1992?

This is N(20). So

$N(20) = 4000*2^20 = 4194304000$

The prediction for the number of transistor per IC in 1992 is of 4,194,304,000

4 0

2 years ago