The answer is D, i.e. the system was solved via elimination
If you multiply the first equation by 5, the system becomes

If you sum the two equations, you get

And so if you substitute the second equation of system A with this new equation, you'll get system B.
U just do 24,678 * .07 to get <span>1727.46</span>
The sum of all the even integers between 99 and 301 is 20200
To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.
In this case, the first even integer will be 100 and the last even integer will be 300.
nth term of the AP = first term + (n-1) x common difference
⇒ 300 = 100 + (n-1) x 2
Therefore, n = (200 + 2 )/2 = 101
That is, there are 101 even integers between 99 and 301.
Sum of the 'n' terms in an AP = n/2 ( first term + last term)
= 101/2 (300+100)
= 20200
Thus sum of all the even integers between 99 and 301 = 20200
Learn more about arithmetic progressions at brainly.com/question/24592110
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Answer:
Step-by-step explanation:
multiply 0.83 by 0.06 = 0.0498
multiply 0.17 by 0.52 and add that to the first one
which gives you the prob of winning of 0.1382
Answer:
The prediction for the number of transistor per IC in 1992 is of 4,194,304,000
Step-by-step explanation:
Moore's law:
Moore's law states that the number of transistors per IC doubles every year.
Format of the function:
Following Moore's law, t years after our initial estimative, the number of transistors per IC will be given by:

In which N(0) is the initial estimate.
The number of transistors per IC in 1972 seems to be about 4,000 (a rough estimate by eye).
This means that 
So

What would you predict the number of transistors per IC to be 20 years later, in 1992?
This is N(20). So

The prediction for the number of transistor per IC in 1992 is of 4,194,304,000