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dimulka [17.4K]
4 years ago
12

Every year, a teacher surveys his students about the number of hours a week they watch television. In 2002, his students watched

an average of 12 hours of television per week. In 2012, the number of hours spent watching television decreased to five per week. What is the percent decrease in the hours of television watched, rounded to the nearest tenth?
Mathematics
2 answers:
lapo4ka [179]4 years ago
9 0

Answer:58.3%

Sorry my sisster helped me do this one and i need to get her notes then i will post them to explain.

Ray Of Light [21]4 years ago
4 0
58.3 percent rounded to the nearest tenth
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what is the prime factorization of 55^5 x 65 x 9^15 and why? A. 3^15 * 5^6 *11^5*13 B. 3^30 *5^6 *11^5 *13 C.3^30 * 5^6 *11 * 13
leonid [27]

Answer:

B

Step-by-step explanation:

1. Lets focus on 55^5

55^5 = 11^5 * 5^5

2. now on 65

65 = 5 * 13

3. now on 9^15

9^15=(3^2)^15 = 3^30

4. combine all three parts

11^5 * 5^5 * 5 * 13 * 3^30 = 11^5*5^6*13*3^30

so our answer is B

7 0
3 years ago
Find derivative problem<br> Find B’(6)
dalvyx [7]

Answer:

B^\prime(6) \approx -28.17

Step-by-step explanation:

We have:

\displaystyle B(t)=24.6\sin(\frac{\pi t}{10})(8-t)

And we want to find B’(6).

So, we will need to find B(t) first. To do so, we will take the derivative of both sides with respect to x. Hence:

\displaystyle B^\prime(t)=\frac{d}{dt}[24.6\sin(\frac{\pi t}{10})(8-t)]

We can move the constant outside:

\displaystyle B^\prime(t)=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)]

Now, we will utilize the product rule. The product rule is:

(uv)^\prime=u^\prime v+u v^\prime

We will let:

\displaystyle u=\sin(\frac{\pi t}{10})\text{ and } \\ \\ v=8-t

Then:

\displaystyle u^\prime=\frac{\pi}{10}\cos(\frac{\pi t}{10})\text{ and } \\ \\ v^\prime= -1

(The derivative of u was determined using the chain rule.)

Then it follows that:

\displaystyle \begin{aligned} B^\prime(t)&=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)] \\ \\ &=24.6[(\frac{\pi}{10}\cos(\frac{\pi t}{10}))(8-t) - \sin(\frac{\pi t}{10})] \end{aligned}

Therefore:

\displaystyle B^\prime(6) =24.6[(\frac{\pi}{10}\cos(\frac{\pi (6)}{10}))(8-(6))- \sin(\frac{\pi (6)}{10})]

By simplification:

\displaystyle B^\prime(6)=24.6 [\frac{\pi}{10}\cos(\frac{3\pi}{5})(2)-\sin(\frac{3\pi}{5})] \approx -28.17

So, the slope of the tangent line to the point (6, B(6)) is -28.17.

5 0
3 years ago
CDs, savings accounts, and savings bonds are examples of _____. A. savings instruments B. savings accounts C. investment returns
krek1111 [17]

Answer:

Correct answer is A

Step-by-step explanation:

7 0
3 years ago
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What is the MAD of the data set?
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The answer to your question is 2.4

3 0
3 years ago
Please help me i have a test in 15 minutes please say a b c or d it’s the top one
ivanzaharov [21]
Its b !!!!!!!!!!!!!!!!!!!!!!!!!!!!!
6 0
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