Answer:
0.323 = 32.3% probability that the director chooses 3 boy kittens and 5 girl kittens.
Step-by-step explanation:
The kittens are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.
Hypergeometric distribution:
The probability of x sucesses is given by the following formula:

In which:
x is the number of sucesses.
N is the size of the population.
n is the size of the sample.
k is the total number of desired outcomes.
Combinations formula:
is the number of different combinations of x objects from a set of n elements, given by the following formula.

A TV studio has brought in 8 boy kittens and 10 girl kittens for a cat food commercial.
This means that 
We want 3 boys, so 
The director is going to choose 8 of these kittens at random to be in the commercial.
This means that 
What is the probability that the director chooses 3 boy kittens and 5 girl kittens?
This is P(X = 3).


0.323 = 32.3% probability that the director chooses 3 boy kittens and 5 girl kittens.
Answer:
x = -4
Step-by-step explanation:
EM = 5x
ET is half of EM so this statement is true: 5x = 2(3x + 2)
Solve for x.
5x = 2(3x +2)
Distribute 2.
5x = 6x + 4
Isolate x.
-x = 4
Divide -1 out.
x = -4
A) n(a) = 25 + 15 = 40
b) n(b) = 42+15 =57
c) n (a U b) = 25 +15+ 42 = 82
d) n (a') = 42
e) n(b') = 25
f) n(a intersection b)' = 82-15 = 67
g) n (a U b)' = 14
h) n (a' intersection b') = 14
i) n (a' U b') = 42 + 25 +14 = 81
hope i helped a bit .. :-)