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Kazeer [188]
3 years ago
12

If P(x) = 8x and R(x) = 9x -8, find P(x) • R(x).​

Mathematics
1 answer:
Airida [17]3 years ago
8 0

Answer:

Given

P( x) = 8x

R ( x) = 9x - 8

Step-by-step explanation:

<em>P(</em><em>x</em><em>)</em><em> </em><em>.</em><em> </em><em>R </em><em>(</em><em> </em><em>x</em><em>) </em>

<em>=</em><em> </em><em>8x </em><em>(</em><em> </em><em>9x </em><em>-</em><em> </em><em>8</em><em> </em><em>)</em>

<em>=</em><em> </em><em>72x</em><em>^</em><em>2</em><em> </em><em> </em><em>-</em><em> </em><em>64x</em>

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6 0
3 years ago
A commuter crosses one of three bridges, A, B, or C, to go home from work. The commuter crosses bridge A with probability 1/3, c
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Answer:

0.1333 = 13.33% probability that bridge B was used.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Arrives home by 6 pm

Event B: Bridge B used.

Probability of arriving home by 6 pm:

75% of 1/3(Bridge A)

60% of 1/6(Bridge B)

80% of 1/2(Bridge C)

So

P(A) = 0.75*\frac{1}{3} + 0.6*\frac{1}{6} + 0.8*\frac{1}{2} = 0.75

Probability of arriving home by 6 pm using Bridge B:

60% of 1/6. So

P(A \cap B) = 0.6*\frac{1}{6} = 0.1

Find the probability that bridge B was used.

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.1}{0.75} = 0.1333

0.1333 = 13.33% probability that bridge B was used.

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3 years ago
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Step-by-step explanation:

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