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Kazeer [188]
3 years ago
12

If P(x) = 8x and R(x) = 9x -8, find P(x) • R(x).​

Mathematics
1 answer:
Airida [17]3 years ago
8 0

Answer:

Given

P( x) = 8x

R ( x) = 9x - 8

Step-by-step explanation:

<em>P(</em><em>x</em><em>)</em><em> </em><em>.</em><em> </em><em>R </em><em>(</em><em> </em><em>x</em><em>) </em>

<em>=</em><em> </em><em>8x </em><em>(</em><em> </em><em>9x </em><em>-</em><em> </em><em>8</em><em> </em><em>)</em>

<em>=</em><em> </em><em>72x</em><em>^</em><em>2</em><em> </em><em> </em><em>-</em><em> </em><em>64x</em>

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4 0
3 years ago
If a manufacturer conducted a survey among randomly selected target market households and wanted to be 95​% confident that the d
katen-ka-za [31]

Answer:

We need a sample size of least 119

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

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The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Sample size needed

At least n, in which n is found when M = 0.09

We don't know the proportion, so we use \pi = 0.5, which is when we would need the largest sample size.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.09 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.09\sqrt{n} = 1.96*0.5

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We need a sample size of least 119

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