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3 years ago

3 cm, 7 cm, 7 cm, 7 cm, 9 cm, 11 cm, 12 cm what is the mean of the data set?

Mathematics

2 answers:

yarga [219]3 years ago

6 0

Answer: 8cm

Step-by-step explanation:

To calculate the mean , we will sum up all the data given and divide by the total number , that is

mean = $3+7+7+7+9+11+12 / 7$

$= 56/7$

$=8$

Therefore:

mean = $8cm$

lisabon 2012 [21]3 years ago

5 0

Answer:

The mean for this question is 8.

Step-by-step explanation:

You add 3+7+7+7+9+11+12 which would equal 56then, you would divide it by how ever many numbers there are so in this case you would divide it by 7.

You might be interested in

Which fraction, in lowest terms, is equivalent to the decimal 0.5?

BARSIC [14]

Answer:

1/2

Step-by-step explanation:

The decimal 0.5 is equal to the fraction 1/2.

it can also be, 0.5 represent the fraction 5/10.

8 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=8%20-%20%20%7B2%7D%5E%7B2%7D%20%20%2B%203%20-%205" id="TexFormula1" title="8 - {2}^{2} + 3 -

Vlad1618 [11]

The answer should be 8+[(2^2)+3]-5

Hope this helps!

3 0

3 years ago

The speed with which utility companies can resolve problems is very important. GTC, the Georgetown Telephone Company, reports it

brilliants [131]

Answer:

(a) 11.25 and 1.68

(b) 0.1651

(c) 0.3903

(d) 0.6865

Step-by-step explanation:

We are given that GTC, the Georgetown Telephone Company, reports it can resolve customer problems the same day they are reported in 75% of the cases and suppose the 15 cases reported today are representative of all complaints.

This situation can be represented through Binomial distribution as;

$P(X=r)= \binom{n}{r}p^{r}(1-p)^{n-r} ; x = 0,1,2,3,....$

where, n = number of trials (samples) taken = 15

r = number of success

p = probability of success which in our question is % of cases in

which customer problems are resolved on the same day, i.e.;75%

So, here X ~ $Binom(n=15,p=0.75)$

(a) Expected number of problems to be resolved today = E(X)

E(X) = $\mu$ = n * p = 15 * 0.75 = 11.25

Standard deviation = $\sigma$ = $\sqrt{n*p*(1-p)}$ = $\sqrt{15*0.75*(1-0.75)}$ = 1.68

(b) Probability that 10 of the problems can be resolved today = P(X = 10)

P(X = 10) = $\binom{15}{10}0.75^{10}(1-0.75)^{15-10}$

= $3003*0.75^{10} *0.25^{5}$ = 0.1651

= $\binom{15}{10}0.75^{10}(1-0.75)^{15-10}+\binom{15}{11}0.75^{11}(1-0.75)^{15-11}$

= $3003*0.75^{10} *0.25^{5} + 1365*0.75^{11} *0.25^{4}$ = 0.3903

(d) Probability that more than 10 of the problems can be resolved today is

given by = P(X > 10)

P(X > 10) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)

= $\binom{15}{11}0.75^{11}(1-0.75)^{15-11}+\binom{15}{12}0.75^{12}(1-0.75)^{15-12} + \binom{15}{13}0.75^{13}(1-0.75)^{15-13}+\binom{15}{14}0.75^{14}(1-0.75)^{15-14} + \binom{15}{15}0.75^{15}(1-0.75)^{15-15}$