Answer: C=[ (10) x (19.60)÷ (8)]
Step-by-step explanation:
Given , The cost of 8 books = $ 19.60
Then, By UNITARY method , the cost of one book = ( Cost of 8 books ) ÷ ( 8)
i.e. The cost of one book = ($19.60) ÷ ( 8) ...(i)
Now , cost of 10 books = (10) x (Cost of one book)
From (i) , we get
Cost of 10 books =$[ (10) x (19.60)÷ (8)]
Let C be the cost of 10 books ( in dollars) .
So , the equation would help determine the cost of 10 :
C=[ (10) x (19.60)÷ (8)]
Answer:
i think 27
Step-by-step explanation:
27 X 4/3y=36y
Answer: Could you check if you can make the question more visible?
Step-by-step explanation:
Answer:
D = L/k
Step-by-step explanation:
Since A represents the amount of litter present in grams per square meter as a function of time in years, the net rate of litter present is
dA/dt = in flow - out flow
Since litter falls at a constant rate of L grams per square meter per year, in flow = L
Since litter decays at a constant proportional rate of k per year, the total amount of litter decay per square meter per year is A × k = Ak = out flow
So,
dA/dt = in flow - out flow
dA/dt = L - Ak
Separating the variables, we have
dA/(L - Ak) = dt
Integrating, we have
∫-kdA/-k(L - Ak) = ∫dt
1/k∫-kdA/(L - Ak) = ∫dt
1/k㏑(L - Ak) = t + C
㏑(L - Ak) = kt + kC
㏑(L - Ak) = kt + C' (C' = kC)
taking exponents of both sides, we have

When t = 0, A(0) = 0 (since the forest floor is initially clear)


So, D = R - A =

when t = 0(at initial time), the initial value of D =
