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Mamont248 [21]
3 years ago
5

What is the greatest product you can make by multiplying two 2-digit numbers? Explain.

Mathematics
2 answers:
Anestetic [448]3 years ago
5 0
9801
99 is the greatest 2 digit number so if you do 99x99 you will get 9801
cricket20 [7]3 years ago
4 0

Answer:

basically to answer this we have to talk about alternate timelines and parallel universes.

Step-by-step explanation: numbers are never ending which means that 1*2 =2*2=4*2=8 so on forever even into the numbers where it has a "e +11" at the end and forever and past that just keep multiplying by 2 forever until you reach nonexistent numbers

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8 books cost \$19.60$19.60dollar sign, 19, point, 60.
snow_tiger [21]

Answer: C=[ (10) x (19.60)÷ (8)]

Step-by-step explanation:

Given , The cost of 8 books = $ 19.60

Then, By UNITARY method , the cost of one book = ( Cost of 8 books ) ÷ ( 8)

i.e. The cost of one book = ($19.60) ÷ ( 8) ...(i)

Now , cost of 10 books = (10) x (Cost of one book)

From (i) , we get

Cost of 10 books =$[ (10) x (19.60)÷ (8)]

Let C be the cost of 10 books ( in dollars) .

So , the equation would help determine the cost of 10 :

C=[ (10) x (19.60)÷ (8)]

7 0
3 years ago
Imena's math test scores are 83, 93, 78, 89, and 83. She has one more math test this semester. What score most she get on the te
marshall27 [118]
87 is the median because 83 and 87's average is 85.
8 0
3 years ago
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How does 4/3y = 36??????????
omeli [17]

Answer:

i think 27

Step-by-step explanation:

27 X 4/3y=36y

6 0
3 years ago
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Which graph represents an exponential function?
emmasim [6.3K]

Answer: Could you check if you can make the question more visible?

Step-by-step explanation:

7 0
3 years ago
Litter such as leaves falls to the forest floor, where the action of insects and bacteria initiates the decay process. Let A be
Travka [436]

Answer:

D = L/k

Step-by-step explanation:

Since A represents the amount of litter present in grams per square meter as a function of time in years, the net rate of litter present is

dA/dt = in flow - out flow

Since litter falls at a constant rate of L  grams per square meter per year, in flow = L

Since litter decays at a constant proportional rate of k per year, the total amount of litter decay per square meter per year is A × k = Ak = out flow

So,

dA/dt = in flow - out flow

dA/dt = L - Ak

Separating the variables, we have

dA/(L - Ak) = dt

Integrating, we have

∫-kdA/-k(L - Ak) = ∫dt

1/k∫-kdA/(L - Ak) = ∫dt

1/k㏑(L - Ak) = t + C

㏑(L - Ak) = kt + kC

㏑(L - Ak) = kt + C'      (C' = kC)

taking exponents of both sides, we have

L - Ak = e^{kt + C'} \\L - Ak = e^{kt}e^{C'}\\L - Ak = C"e^{kt}      (C" = e^{C'} )\\Ak = L - C"e^{kt}\\A = \frac{L}{k}  - \frac{C"}{k} e^{kt}

When t = 0, A(0) = 0 (since the forest floor is initially clear)

A = \frac{L}{k}  - \frac{C"}{k} e^{kt}\\0 = \frac{L}{k}  - \frac{C"}{k} e^{k0}\\0 = \frac{L}{k}  - \frac{C"}{k} e^{0}\\\frac{L}{k}  = \frac{C"}{k} \\C" = L

A = \frac{L}{k}  - \frac{L}{k} e^{kt}

So, D = R - A =

D = \frac{L}{k} - \frac{L}{k}  - \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{kt}

when t = 0(at initial time), the initial value of D =

D = \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{k0}\\D = \frac{L}{k} e^{0}\\D = \frac{L}{k}

4 0
3 years ago
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