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Varvara68 [4.7K]

3 years ago

15

What are the accounting concepts

1 answer:

qwelly [4]3 years ago

5 0

The accounting concepts are business entity, going concern, historical cost, conservatism, consistency etc.

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What is the value of x in the figure shown below?

Julli [10]

Answer:

110°

Step-by-step explanation:

Parallelograms have angles equal to the angle opposite to it, in this case the 110°

6 0

3 years ago

in the given figure the side BC is extended to D.IF BE is the bisectorof angle ABC and CE is the bisector of angle ACD THEN PROV

Harlamova29_29 [7]

Answer:

bc or 2.5

Step-by-step explanation:

I think thats right

3 0

3 years ago

kite is a quadrilateral with two pairs of adjacent, congruent sides. The vertex angles are those angles in between the pairs of

just olya [345]

If we have a kite ABCD where AB = CD and DC = CA.
Let E be a midpoint between BC
Since triangle ABC is an isosceles triangle, ray BE bisects angle ABC and is perpendicular to AC.
So, angle ABE = CBE.
<span>Since also triangle CDA is isosceles, line DE is perpendicular to AC for the same reason. Therefore, AC is perpendicular to BD.</span>

3 0

3 years ago

What is the equation for this line?

zzz [600]

Answer:

The equation of the line is y = 2x - 3

Step-by-step explanation:

The form of the linear equation is y = m x + b, where

m is the slope of the line, $m=\frac{y2-y1}{x2-x1}$

b is the y-intercept (value y at x = 0)

Let us take two points on the line to find its equation

∵ Points (3, 3) and (0, -3) lie on the line

∴ x1 = 3 and y1 = 3

∴ x2 = 0 and y2 = -3

→ Use the rule of the slope above to find m

∵ $m=\frac{-3-3}{0-3}=\frac{-6}{-3}=2$

∴ m = 2

→ Substitute its value in the form of the equation above

∴ y = 2x + b

∵ b is the value of y at x = 0

∵ y = -3 at x = 0

∴ b = -3

→ Substitute it in the equation above

∴ y = 2x + -3

→ Remember (+)(-) = (-)

∴ y = 2x - 3

∴ The equation of the line is y = 2x - 3

7 0

4 years ago

The velocity of an object is given by the following function defined on a specified interval. Approximate the displacement of th

harkovskaia [24]

Answer:

The displacement of the object on this intervals is 1.33 m.

Step-by-step explanation:

Given that,

The function of velocity is

$v=\dfrac{1}{2t+4}\ m/s$

For 0 ≤ t ≤8 , n = 2

We need to calculate the intervals

Using formula for intervals

For, n = 1

$\Delta x=\dfrac{t_{f}-t_{i}}{n}$

$\Delta x=\dfrac{8-0}{2}$

$\Delta x=4$

So, The intervals are (0,4), (4,8)

We need to calculate the velocity

Using given function

$v=\dfrac{1}{2t+4}$

For first interval (0,4),

Put the value into the formula

$v_{0}=\dfrac{1}{2\times0+4}$

$v_{0}=\dfrac{1}{4}$

For first interval (4,8),

Put the value into the formula

$v_{4}=\dfrac{1}{2\times4+4}$

$v_{4}=\dfrac{1}{12}$

We need to calculate the total displacement

Using formula of displacement

$D=(v_{0}+v_{4})\times(\Delta x)$

Put the value into the formula

$D=(\dfrac{1}{4}+\dfrac{1}{12})\times4$

$D=1.33\ m$

Hence, The displacement of the object on this intervals is 1.33 m.

5 0

4 years ago