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coldgirl [10]
3 years ago
14

How do you do question 4, 5 and 6? I don't understand :(

Mathematics
1 answer:
AleksandrR [38]3 years ago
6 0
Sorry i would help but i dont understand either. D:
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Christopher works at the power plant for the southwest part of his home state. For peak operational performance, his department
Licemer1 [7]

Answer:

B) To maintain peak performance for every 50 generators, there are 10 inspectors.

Step-by-step explanation:

For peak operational:

3 electricians for each generator.  ⇒  1 Generator : 3 Electricians

4 inspectors for every 60 electricians. ⇒  60 Electricians : 4 Inspectors

Now, the number of generators the state has now = 50

Let us assume the number of  inspectors  required by the power plant  = m

Now, from the given ratios:

For, 3 electrician there  is 1 generator

⇒ For, 3 x 20 Electrician  there is 1  x 20 Generators.

or, for 60 Electrician there are 20 Generators.   (1)

Also, for 60 Electrician there are 4 inspectors.    (2)

⇒From (1) and (2), we get:

For every 20 generators, there are 4 inspectors.

And, from what we have assumed  For every 50 generators, there are m inspectors.

So, by the RATIO OF PROPORTION:

\frac{20}{4}  = \frac{50}{m}\\ \implies  m = 50 \times\frac{4}{20}  = 10

or, m = 10

Hence, to maintain peak performance for every 50 generators, there are 10 inspectors.

3 0
3 years ago
Solve the equation <br> X+ (-15) = 9
ella [17]

Step-by-step explanation:

x + ( - 15) = 9

x - 15 = 9

x = 9  + 15

x = 24

3 0
3 years ago
Read 2 more answers
Integration of (cosec^2 x-2005)÷cos^2005 x dx is
kondor19780726 [428]
We are asked in the problem to evaluate the integral of <span>(cosec^2 x-2005)÷cos^2005 x dx. The function is an example of a complex function with a degree that is greater than one and that uses special rules to integrate the function via the trigonometric functions. For example, we integrate 
2005/cos^2005x dx which is equal to 2005 sec^2005 x since sec is the inverse of cos. The integral of this function when n >3 is equal to I=</span><span>∫<span>sec(n−2)</span>xdx+∫tanx<span>sec(n−3)</span>x(secxtanx)dx
Then, 
</span><span>∫tanx<span>sec(<span>n−3)</span></span>x(secxtanx)dx=<span><span>tanx<span>sec(<span>n−2)</span></span>x/(</span><span>n−2)</span></span>−<span>1/(<span>n−2)I
we can then integrate the function by substituting n by 3.

On the first term csc^2 2005x / cos^2005 x we can use the trigonometric identity csc^2 x = 1 + cot^2 x to simplify the terms</span></span></span>
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3 years ago
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