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coldgirl [10]
4 years ago
14

How do you do question 4, 5 and 6? I don't understand :(

Mathematics
1 answer:
AleksandrR [38]4 years ago
6 0
Sorry i would help but i dont understand either. D:
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A b c or d please hurry thanks!
otez555 [7]

Answer:

C)  a = 10√3, b = 5√3, c = 15 , d = 5

Step-by-step explanation:

Here we use the ratio of 30, 60, 90 degree triangle.

The ratio of sides, 1:√3:2

2x = 10

x = 5

d = 5

b = 5√3

c = 5√3√3

c = 5*3 = 15

c = 15

a = 2(5√3)

a = 10√3

Therefore, a = 10√3, b = 5√3, c = 15 and d = 5

Thank you.

8 0
3 years ago
Read 2 more answers
20 POINTS‼️‼️Which of the following does NOT represent the number of months in a year?
NeTakaya

Answer:

B because when you multiply the first number by twelve the first two are correct but the second ones are not

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Find two positive consecutive odd integers such that square of the smaller integer is 10 more than the larger integer
Otrada [13]

Let 2n+1 be the smaller integer. The larger integer is then 2n+3, and we have

(2n+1)^2=10+(2n+3)\implies4n^2+4n+1=2n+13

\implies4n^2+2n-12=0

\implies2n^2+n-6=0

\implies(2n-3)(n+2)=0

\implies 2n-3=0\text{ or }n+2=0

\implies n=\dfrac32\text{ or }n=-2

We omit n=-2, since 2(-2)+1=-3 is negative.

Then for n=\dfrac32 we find 2\left(\dfrac32\right)+1=4, but this is not odd.

There are no consecutive odd integers that satisfy the given condition!

3 0
3 years ago
This histogram shows the numbers of people who volunteered for community service and the number of hours they worked.
Inga [223]
The correct answer is :85

You can find this out because you would count by fives so : 5, 10, 15, 20, 25 so there are 25 volunteers in the 11-15 hours worked so you would add that to the 21-25 also known as 10 hours worked you also have to add 16-20 also known as 50 so add all that and you get  50 + 25 + 10 = 85

So it's 85
I hope this helped! =)
4 0
3 years ago
Simplify the following monomials pls
velikii [3]

Answer:

1.) a^4b

2.) p^3q^4

3.) 2n^42n^4

4.) 5xy^2z

5.) 2a^3b^5

I hope this helps:

4 0
3 years ago
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