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I am Lyosha [343]
3 years ago
10

A swift can fly at 160km/h. what is the speed in m/s? show clearly how you worked out your answer.

Mathematics
2 answers:
Oduvanchick [21]3 years ago
7 0

Step-by-step explanation:

Given \: speed \:  = 160km| h  \\ To \: find \: speed \: in \: m|s \\ Solution \: speed \:  = 160km|h \\  = (160 \times \frac{5}{18}) \: m|s \\  =  \frac{800}{18} m|s \\  = 44.44m|s \\ Hence \: speed \:  = 44.44m|s...

<em>hOpE</em><em> </em><em>iT</em><em> </em><em>hElPs</em><em> YoU</em>

<h3><em><u>I</u></em><em><u> </u></em><em><u>nEEd</u></em><em><u> bRainLIeST</u></em></h3>
DanielleElmas [232]3 years ago
7 0

Answer:

\huge\boxed{\sf Speed = 44.44 \ m/s}

Step-by-step explanation:

Speed = 160 km / hr

To convert km/hr to m/s, we multiply it by \sf \frac{10}{36}

<u>Hence,</u>

\displaystyle Speed = 160 \times \frac{10}{36} \ m/s\\\\Speed = \frac{1600}{36} \ m/s\\\\Speed = 44.44 \ m/s\\\\\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3><h3>Peace!</h3>
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2 years ago
What is the length of BC , rounded to the nearest tenth?
Arte-miy333 [17]

Step 1

In the right triangle ADB

<u>Find the length of the segment AB</u>

Applying the Pythagorean Theorem

AB^{2} =AD^{2}+BD^{2}

we have

AD=5\ units\\BD=12\ units

substitute the values

AB^{2}=5^{2}+12^{2}

AB^{2}=169

AB=13\ units

Step 2

In the right triangle ADB

<u>Find the cosine of the angle BAD</u>

we know that

cos(BAD)=\frac{adjacent\ side }{hypotenuse}=\frac{AD}{AB}=\frac{5}{13}

Step 3

In the right triangle ABC

<u>Find the length of the segment AC</u>

we know that

cos(BAC)=cos (BAD)=\frac{5}{13}

cos(BAC)=\frac{adjacent\ side }{hypotenuse}=\frac{AB}{AC}

\frac{5}{13}=\frac{AB}{AC}

\frac{5}{13}=\frac{13}{AC}

solve for AC

AC=(13*13)/5=33.8\ units

Step 4

<u>Find the length of the segment DC</u>

we know that

DC=AC-AD

we have

AC=33.8\ units

AD=5\ units

substitute the values

DC=33.8\ units-5\ units

DC=28.8\ units

Step 5

<u>Find the length of the segment BC</u>

In the right triangle BDC

Applying the Pythagorean Theorem

BC^{2} =BD^{2}+DC^{2}

we have

BD=12\ units\\DC=28.8\ units

substitute the values

BC^{2}=12^{2}+28.8^{2}

BC^{2}=973.44

BC=31.2\ units

therefore

<u>the answer is</u>

BC=31.2\ units

8 0
3 years ago
Read 2 more answers
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