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Bess [88]
4 years ago
15

How do I set this up?

Mathematics
1 answer:
sdas [7]4 years ago
5 0
Identify the length of both bases. The bases are the two Identify parallel sides of the trapezoid.

12 and 6 are our bases.

...Add the lengths of the bases.

12+6 = 18

..Multiply the sum of the lengths of the bases by the height. ...Divide the result by two.

18×5= 90
90÷2= 45

The area is 45.
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Erik Buys 2.5 pounds of cashews. If each pound of cashews cost $7.70, how much will he pay for the cashews?
Colt1911 [192]

Answer:

$19.25

Step-by-step explanation:

$7.70 x 2.5 = $19.25

brainliest please ;)

5 0
3 years ago
What is the least common multiple (LCM) of 5 and 12?
geniusboy [140]

The least common multiple of 5 and 12 is 60.

4 0
3 years ago
Greta cut a ribbon into 12 pieces. Each piece was 6 inches long. Write and solve an equation to find the length of the ribbon sh
ANEK [815]

Answer:

72

Step-by-step explanation:

12 pieces of ribbon was 6 inch long so you would multiply 12 and 6 and get 72 and that's how much she started with.

5 0
3 years ago
A homeowner's backyard is a rectangle with width 18 yards long and length 16 yards long. They plan to put in a square pool with
Ugo [173]

Answer:

Step-by-step explanation:

Given the dimension of the  homeowner's backyard to be width 18 yards long and length 16 yards long, the area of the rectangular backyard id expreesed as;

Area of rectangle = Length * Width

Area of the rectangular backyard = 18yards * 16yards

Area of the rectangular backyard = 288yards²

If they plan to put in a square pool with side length 5 yards long in the backyard, the area of the pool = 5yd*5yd = 25yd²

The remaining area that will contain the tiles = Area of the rectangular backyard -  area of the pool

The remaining area that will contain the tiles = 288yd² - 25yd² = 263yd²

<em>Note that we cannot determine the amount of tiles they need to buy since we are not given the dimension of each tile to use</em>. The area needed for the tiles for the rest of the backyard is therefore 263yd².

Amount of tiles needed to buy can be expressed as 263/dimension of a tile.

4 0
3 years ago
Пожалуйста,очень нужны 4,5,6<br> Срочнооооооо<br> Спасибо заранее
kifflom [539]
B. is the answer to your question!! Hope this helps!! :D
4 0
4 years ago
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