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Eduardwww [97]
3 years ago
7

A homeowner's backyard is a rectangle with width 18 yards long and length 16 yards long. They plan to put in a square pool with

side length 5 yards long in the backyard and then want to put tile in the rest of the entire backyard. How much tile do they need to buy?
Mathematics
1 answer:
Ugo [173]3 years ago
4 0

Answer:

Step-by-step explanation:

Given the dimension of the  homeowner's backyard to be width 18 yards long and length 16 yards long, the area of the rectangular backyard id expreesed as;

Area of rectangle = Length * Width

Area of the rectangular backyard = 18yards * 16yards

Area of the rectangular backyard = 288yards²

If they plan to put in a square pool with side length 5 yards long in the backyard, the area of the pool = 5yd*5yd = 25yd²

The remaining area that will contain the tiles = Area of the rectangular backyard -  area of the pool

The remaining area that will contain the tiles = 288yd² - 25yd² = 263yd²

<em>Note that we cannot determine the amount of tiles they need to buy since we are not given the dimension of each tile to use</em>. The area needed for the tiles for the rest of the backyard is therefore 263yd².

Amount of tiles needed to buy can be expressed as 263/dimension of a tile.

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