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3 years ago

Which answered describe the shape below ?

Mathematics

1 answer:

Vitek1552 [10]3 years ago

5 0

Answer:

B. Trapezoid

Step-by-step explanation:

Trapezoid is a quadrilateral with only one pair of parallel sides, so it's "B".

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Made up of quantities and the operations performed on them what is this vocab word

maxonik [38]

Equation. This word may fit your definition of a set of values or numbers –intergers- coupled with basic operations. Equation is mathematical form of body where there are two adjacent corners which aims as the word says, equation. Take for instance in illustration 2x + 5x = 7x. This “equation” is composed of these numbers with unknowns and the operation of addition with them. When you have solved for 7x in the example, it only shows that to attain “equation”, solution is performed and done. Hence, these two works relationally.

7 0

3 years ago

2√m^2 if m is greater than or equal to 0

iris [78.8K]

Answer:

$\displaystyle \boxed{|2m| }$

Step-by-step explanation:

we are given that

$\displaystyle 2 \sqrt{ {m}^{2} }$

since m is greater than or equal to 0 it's a positive number therefore, the square root of m is defined and recall that √x²=|x| thus

$\displaystyle \boxed{2 |m|}$

remember that,|a|•|x|=|ax| hence,

$\displaystyle \boxed{ |2m|}$

and we're done!

3 0

2 years ago

Read 2 more answers

Scientist can determine the age of ancient objects by a method called radiocarbon dating. The bombardment of the upper atmospher

Artemon [7]

Answer: 2500 years

Step-by-step explanation:

I'm not quite sure if I'm doing this right myself but I'll give it a shot.

We use this formula to find half-life but we can just plug in the numbers we know to find t.

$A(t)=A_{0}(1/2)^t^/^h$

We know half-life is 5730 years and that the parchment has retained 74% of its Carbon-14. For $A_{0$ let's just assume that there are 100 original atoms of Carbon-14 and for A(t) let's assume there are 74 Carbon-14 atoms AFTER the amount of time has passed. That way, 74% of the C-14 still remains as 74/100 is 74%. Not quite sure how to explain it but I hope you get it. h is the last variable we need to know and it's just the half-life, which has been given to us already, 5730 years, so now we have this.

$74=100(1/2)^t^/^5^7^3^0$

Now, solve. First, divide by 100.

$0.74=(0.5)^t^/^5^7^3^0$

Take the log of everything

$log(0.74)=\frac{t}{5730} log(0.5)$

Divide the entire equation by log (0.5) and multiply the entire equation by 5730 to isolate the t and get

$5730\frac{log(0.74)}{log(0.5)} =t$

Use your calculator to solve that giant mess for t and you'll get that t is roughly 2489.128182 years. Round that to the nearest hundred years, and you'll find the hopefully correct answer is 2500 years.

Really hope that all the equations that I wrote came out good and that that's right, this is definitely the longest answer I've ever written.

5 0

3 years ago

there are 500 hundred pages. if the book has 25 chapters and each chapter is 20 pages long. what is the chance that of randomly

nataly862011 [7]

20/500
0.04 of a chance
because 1 chapter has 20 pages and the book has 500
so the chance of you flipping to chapter 12 out of 500 pages is 4% of a chance

6 0

3 years ago

Use Lagrange multipliers to find the maximum and minimum values of

marusya05 [52]

The Lagrangian is

$L(x,y,\lambda)=x+8y+\lambda(x^2+y^2-4)$