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egoroff_w [7]
3 years ago
9

2√m^2 if m is greater than or equal to 0

Mathematics
2 answers:
mel-nik [20]3 years ago
5 0

Answer:

2m

Step-by-step explanation:

<u>Given </u><u>:</u><u>-</u><u> </u>

  • 2√m² , m is greater than or equal to 0 .

By question,

→ 2√m²

→ 2 * m

→ 2m

iris [78.8K]3 years ago
3 0

Answer:

\displaystyle  \boxed{|2m| }

Step-by-step explanation:

we are given that

\displaystyle 2 \sqrt{  {m}^{2} }

since m is greater than or equal to 0 it's a positive number therefore, the square root of m is defined and recall that √x²=|x| thus

\displaystyle  \boxed{2 |m|}

remember that,|a|•|x|=|ax| hence,

\displaystyle  \boxed{ |2m|}

and we're done!

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15 i think

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Answer:

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The length of a rectangle is 5 units more than the width. The area of the rectangle is 36 units. What is the length, in units, o
sergey [27]

Answer:

11 units

Step-by-step explanation:

Let's do it this way:

Length = l

width = w

initial equation for area is l * w

We know that l = w+5

substitute.

w+5 * w = 36

solve.

6w = 36

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The width is 6 units.

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4 years ago
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Find the length of the curve given by ~r(t) = 1 2 cos(t 2 )~i + 1 2 sin(t 2 ) ~j + 2 5 t 5/2 ~k between t = 0 and t = 1. Simplif
xxMikexx [17]

Answer:

The length of the curve is

L ≈ 0.59501

Step-by-step explanation:

The length of a curve on an interval a ≤ t ≤ b is given as

L = Integral from a to b of √[(x')² + (y' )² + (z')²]

Where x' = dx/dt

y' = dy/dt

z' = dz/dt

Given the function r(t) = (1/2)cos(t²)i + (1/2)sin(t²)j + (2/5)t^(5/2)

We can write

x = (1/2)cos(t²)

y = (1/2)sin(t²)

z = (2/5)t^(5/2)

x' = -tsin(t²)

y' = tcos(t²)

z' = t^(3/2)

(x')² + (y')² + (z')² = [-tsin(t²)]² + [tcos(t²)]² + [t^(3/2)]²

= t²(-sin²(t²) + cos²(t²) + 1 )

................................................

But cos²(t²) + sin²(t²) = 1

=> cos²(t²) = 1 - sin²(t²)

................................................

So, we have

(x')² + (y')² + (z')² = t²[2cos²(t²)]

√[(x')² + (y')² + (z')²] = √[2t²cos²(t²)]

= (√2)tcos(t²)

Now,

L = integral of (√2)tcos(t²) from 0 to 1

= (1/√2)sin(t²) from 0 to 1

= (1/√2)[sin(1) - sin(0)]

= (1/√2)sin(1)

≈ 0.59501

8 0
3 years ago
HELPPPP MEEE OUTTTT???
zhuklara [117]
<h3>Answer:  June 22nd</h3>

=========================================================

Explanation:

1 hour = 60 minutes

1 day = 24 hours

1 day = (24 hrs)*(60 min/1hr) = 24*60 min = 1440 min

1 day = 1440 min

Divide 250,000 minutes over 1440 min to convert from minutes to days

(250,000)/(1440) = 173.611

This means 250,000 minutes is approximately 173.611 days.

We round this down to the nearest whole number because 174 full days means that some portion of minutes has not elapsed just yet. In other words, we're still on day 173. Yes we're past the halfway point, but we're still on this day.

From here, bring out a Day-Of-Year Calendar which will help you locate any day of the year if you know its numeric value, and vice versa. For instance, if you selected any value between 1 and 31, then you'll be on January of that day number. If you selected 32, then you'll be on February 1st since day 32 is one day after day 31 (the last day in January). The largest value of the calendar is either 366 on leapyears or 365 for non-leapyears.

Keep in mind that 2009 is not a leapyear, so that means we won't be involving Feb 29. On non-leapyears, the 173rd day lands on June 22nd.

You could count out the number of days from Jan 1st until you count out 173 days (you should land on June 22). Though I don't recommend this method because it could be error prone and slow.

------------

Side note: Day-Of-Year Calendars are useful if you want to know the timespan between any two days of the year. For instance, June 22 is the 173 day of the year while Oct 9th is the 282 day of the year (I'm focusing on a non-leapyear). The difference in value is 282-173 = 109, meaning that 109 days elapse from June 22 to Oct 9.

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