Answer:
Volume = 16 unit^3
Step-by-step explanation:
Given:
- Solid lies between planes x = 0 and x = 4.
- The diagonals rum from curves y = sqrt(x) to y = -sqrt(x)
Find:
Determine the Volume bounded.
Solution:
- First we will find the projected area of the solid on the x = 0 plane.
A(x) = 0.5*(diagonal)^2
- Since the diagonal run from y = sqrt(x) to y = -sqrt(x). We have,
A(x) = 0.5*(sqrt(x) + sqrt(x) )^2
A(x) = 0.5*(4x) = 2x
- Using the Area we will integrate int the direction of x from 0 to 4 too get the volume of the solid:
V = integral(A(x)).dx
V = integral(2*x).dx
V = x^2
- Evaluate limits 0 < x < 4:
V= 16 - 0 = 16 unit^3
R + b = 146. Supposing that b=r+28,
r + (r+28) = 146, or 2r + 28 = 146.
Simplifying: 2r = 118. Then r = 59, and b = r+28 = 59+28 = 87 blue marbles
3 should be added to the tiles
Answer:
117
Step-by-step explanation:
6/8 = ?/156
156/8 = 19.5
19.5 x 6 = 117
6/8 = 117/156
