Begin by multiplying $15.65 by 0.20 to find what 20% of the regular price is. This gives you 3.13, which in this situation means $3.13.
To find the price with discount subtract 15.65-3.13. This gives you $12.52.
To find out the change, subtract 20-12.52. This gives you $7.48.
So, he will receive $7.48 in change.
Hope this helps!
89 is the mode, it occurs the most (3 times)
89 is also the median, it is the middle number out of the 15 numbers in the data set. It there were 14 numbers you would add the two middle numbers and divide by 2 to get the median.
Answer:
<3=75°
Step-by-step explanation:
Angle 3 and angle 2x+95 are supplementary( supplementary angles add up to 180°)
So <3+2x+95=180
<3+2x=180-95
<3+2x=85( let's call this equation 1)
Next, angle 5 and angle 8x+71 are opposite angles (opposite angles are equal) therefore <5=8x+71
Now, <3 and <5 are co-interior angles(co-interior angles are supplementary)
So <3+8x+71=180
<3+8x=180-71=109
Thus, <3+8x=109(let's call this equation 2)
Now solving equation 1 and 2 simultaneously:
Make <3 the subject of equation 1
<3=85-2x
Put <3=85-2x into equation 2
85-2x+8x=109
6x=24
x=24/6=4
Now, remember that angle 2x+95 becomes
2(4)+95
8+95=103°
Therefore<3=180-105=75°
Answer:
-81 - y
Step-by-step explanation:
To simplify the expression -3[2-(y-5)]-4[3(y+1)-(6-y)(-2)] use order of operations or PEMDAS.
-3[2-(y-5)]-4[3(y+1)-(6-y)(-2)]
-3[2-y+5]-4[3y + 3+12 -2y]
-3[7-y] -12y-12-48+8y
-3[7-y] - 4y - 60
-21 + 3y - 4y - 60
-81 - y
1)
x^2 + 4x - 5
y = --------------------
3x^2 - 12
Vertcial asym => find the x-values for which the equation is not defined and check whether the limit goes to + or - infinite
=> 3x^2 - 12 = 0 => 3x^2 = 12
=> x^2 = 12 / 3 = 4
=> x = +/-2
Limit of y when x -> 2(+) = ( 2^2 + 4(2) - 5) / 0 = - 1 / 0(+) = ∞
Limit of y when x -> 2(-) = - 1 / (0(-) = - ∞
Limit of y when x -> - 2(+) = +∞
Limit of y when x -> - 2(-) = -
=> x = 2 and x = - 2 are a vertical asymptotes
Horizontal asymptote => find whether y tends to a constant value when x -> infinite of negative infinite
Limi of y when x -> - ∞ = 1/3
Lim of y when x -> +∞ = 1/3
=> Horizontal asymptote y = 1/3
x - intercept => y = 0
=>
x^2 + 4x - 5
0 = ------------------ => x ^2 + 4x - 5 = 0
3x^2 - 12
Factor x^2 + 4x - 5 => (x + 5) (x - 1) = 0 => x = - 5 and x = 1
=> x-intercepts x = - 5 and x = 1
Domain: all the real values except x = 2 and x = - 2
2) y = - 2 / (x - 4) - 1
using the same criteria you get:
Vertical asymptote: x = 4
Horizontal asymptote: y = - 1
Domain:all the real values except x = 4
Range: all the real values except y = - 1
3)
x/ (x + 2) + 7 / (x - 5) = 14 / (x^2 - 3x - 10)
factor x^2 - 3x - 10 => (x - 5)(x + 2)
Multiply both sides by (x - 5) (x + 2)
=> x(x - 5) + 7( x + 2) = 14
=> x^2 - 5x + 7x + 14 = 14
=> x^2 + 2x = 0
=> x(x + 2) = 0 => x = 0 and x = - 2 but the function is not defined for x = - 2 so it is not a solution => x = 0
Answer: x = 0
