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mr_godi [17]
3 years ago
9

How much would $500 invested at 5% interest compounded continuously be

Mathematics
1 answer:
vekshin13 years ago
5 0

Answer:

A = $746 (rounded up to nearest cent)

Step-by-step explanation:

A = Pe^{rt}

A = $500 × e^{0.05(8)} = $745.9123488  or $746 (rounded up to nearest cent)

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Evaluate 5!+2!. Thank you!
Ghella [55]

Answer:

122

Step-by-step explanation:

5!=5 x 4 x 3 x 2 x 1 = 120

2!=2 x 1 = 2

120+2=122

7 0
2 years ago
The ratio of Ed's toy cars to Pete's toy cars was initially 5:2. After Ed gave 30 toy cars to Pete, they each had an equal numbe
Slav-nsk [51]

Answer:

140 toy cars

Step-by-step explanation:

The ratio of Ed's toy car to Pete's toy car is initially given as 5:2

Ed gave Pete a total number of 30 cars

Let x represent the greatest common factor that exists between both number

Number of Ed's car is represented as 5x

Number of Pete car is represented as 2x

Since they each have an equal number of cars which is 30 then we can solve for x as follows

5x-30=2x+30

Collect the like terms

5x-2x= 30+30

3x= 60

Divide both sides by the coefficient of x which is 3

3x/3=60/3

x=20

Ed's car is 5x, we substitute 20 for x

5(20)

= 100 cars

Pete car is 2x,we substitute 20 for x

2(20)

= 40 cars

Therefore, the total number of cars can be calculated as follows

= 100+40

= 140 toy cars

Hence they have 140 toy cars altogether

5 0
3 years ago
Read 2 more answers
What’s the answer need it ASAP
geniusboy [140]

Answer:

Step-by-step explanation:nsshs

8 0
3 years ago
Read 2 more answers
17. When a single set of values is randomly divided into two equal groups, explain how the means of these two groups may be very
joja [24]

If you take 2 groups of equal cardinality, it could happen that, for example, many of the higher values go to the first group and therefore, many of the low values go to the second group, making their respective means quite different and different from the original sample mean. This could even go worse due to the possible existence of outliers, that is, values that are far different than the sample mean. An outlier tend to disrup the mean of a sample, but for smaller samples the result is much dramatic.

For example, let X be {1,2,3,4,5,6,7,8,9,100}

The elements of X sum 145, hence the mean of X is 14,5. Let divide X in two groups

Y = {1,2,3,5,9}

Z = {4,6,7,8,100}

The elements of Y sum 20, so its mean is 4

The elements of Z sum 125, so its mean is 25

Both means are quite different from each other and quite different from the mean of X. Note that if we take the mean of the means the result is 4+25/2 = 14,5 which is equal to the mean of X.

7 0
3 years ago
Can someone help me with B? I’m really bad at this kind of stuff. I need help ASAP
Vinil7 [7]

Answer:

D = .44P

Step-by-step explanation:

We need to find the slope of the line

m = (y2-y1)/ (x2-x1)

Using two points

m = (22-4.4) /(50-10)

   = 17.6/40

   = .44 lb/ in^2 ft

We can use the point slope form of the equation

y-y1 = m(x-x1)  where y=D and x=P

D-4.4 = .44 (P-10)

Distribute

D-4.4 = .44P - 4.4

Add 4.4 to each side

D -4.4+4.4 = .44P -4.4+4.4

D = .44P

8 0
3 years ago
Read 2 more answers
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