V=(1/3)hpir^2
lets say this is original, undoubled volume
so o=v=(1/3)hpir^2
so for new volume, or n, that is r to 2r, doubled radius
n=(1/3)hpi(2r)^2
n=(1/3)hpi4r^2
n=4((1/3)hpir^2)
remmember that o=(1/3)hpir^2
n=4(o)
it is 4 times the old one
A cube because it’s already square n can be cut in square cross sections
Answer:9?
Step-by-step explanation: hair
YEA I THINK ITS 4 WHAT HE SAID ABOVE ME
Answer: Your answer would be C) 32.1%
Step-by-step explanation:
With the number of successes needed to be 4 and the total amount of trials (games) for this to be achieved in being 6 you can calculate a percentage based on their currenting winning percentage of .623 (don't forget decimals can be percentages, just move the decimal point over) and you can input all of this into the binomial model equation to get your answer. Please do note also that it would be a different answer entirely if you were to use .500 (50%) as a winning percentage which would be the logical conclusion as any team has a 50/50 chance of winning a given game but instead the question is asking us to calculate this percentage off the already given winning percentage. After inputting the data into the model formula you can conclude the answer to be 32.1% chance of them winning 4 out of the next 6 games. I hope this has been of assistance to you :)
Have a wonderful rest of your day!
