Answer:
We have 197 g of Co-60 after 18 months.
Step-by-step explanation:
We can use the decay equation.

Where:
- M(f) and M(i) are the final and initial mass respectively
- λ is the decay constant (ln(2)/t(1/2))
- t(1/2) is the half-life of Co
- t is the time at the final amount of m
<u>Therefore, we have 197 g of Co-60 after 18 months.</u>
I hope it helps you!
82 X 10-6 glm3of pollutants in the air. ... The weight of 1m3 of air is approximately 1.3 X 103g.Suppose that the volume of air inside of a building is 3 x 106 m3.
Answer:
The y-intercept of this line is 1.
Step-by-step explanation:
We are looking for the y-value when x=0. And that value is 1