Question

Using the transformation T: (x,y) —> (x+2, y+1), find the distance CB

Answer 1

Answer:

The distance between CB is $\sqrt[]{10}$

Step-by-step explanation:

Recall that the transformation T consists of a translation of 2 units to the right and 1 unit up. Then, T preserves distances(which means that it keeps distances between points the same as before applying the transformation). Then, distance CB is the sames as distance C'B'. We will use the distance formula: if we have points (x,y), (z,w) then the distance between them is given by

$\sqrt[]{(x-z)^2+(y-w)^2}$

In our case we have that C'=(0,3), B'=(3,4). Then, the distance between them is

$\sqrt[]{(3-0)^2+(4-3)^2}= \sqrt[]{10}$