Answer:
57 units^2
Step-by-step explanation:
First find the area of the triangle on the left
ABC
It has a base AC which is 9 units and a height of 3 units
A = 1/2 bh = 1/2 ( 9) *3 = 27/2 = 13.5
Then find the area of the triangle on the right
DE
It has a base AC which is 6 units and a height of 1 units
A = 1/2 bh = 1/2 ( 6) *1 = 3
Then find the area of the triangle on the top
It has a base AC which is 3 units and a height of 3 units
A = 1/2 bh = 1/2 ( 3) *3 = 9/2 = 4.5
Then find the area of the rectangular region
A = lw = 6*6 = 36
Add them together
13.5+3+4.5+36 =57 units^2
Answer:
I didn't understand your question
Here ya go. I hope this helps! :) (It was much easier to do this than to try and type it out, in my opinion)
Answer:
Yes
Step-by-step explanation:
Answer:
DL/dt = 17 mph
Step-by-step explanation:
The ships and the port shape a right triangle
Ship going west ( x-direction) is traveling at 15 mph
Ship going north (y-direction) is traveling at 10 mph
The distance L between ships is:
L² = x² + y²
Tacking derivatives on both sides of the equation with respect to time
we get
2*L*DL/dt = 2*x*Dx/dt + 2*y*Dy/dt (1)
In that equation we know:
Dx/dt = 15 mph
Dy/dt = 10 mph
At the moment ship traveling from the east is at 3 miles from the port
then x = 3 m and the other ship is at 4 miles north
then by Pythagoras theorem
L = √ 3² + 4² L = 5
By substitution in equation 1
2*5*DL/dt = 2*3*15 + 2*4*10
10* DL/dt = 90 + 80
DL/dt = 170 / 10
DL/dt = 17 mph
