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rodikova [14]
3 years ago
8

What's 4 (-x + 1 ) = -2 (x + 2) ?

Mathematics
1 answer:
alexira [117]3 years ago
5 0

Answer:

x = 4

Step-by-step explanation:

Simplify then isolate x

4 (-x + 1 ) = -2 (x + 2)     Distribute across brackets

-4x + 4 = -2x - 4      Add 2x to both sides

-2x + 4 = -4     Subtract 4 from both sides

-2x = -8      Divide both sides by -2

x = 4

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The value of A is 20

Step-by-step explanation:

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71x - 1 + 20x + 90 = 180

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4 years ago
The sum of squares of three consecutive numbers is 77 find the numbers​
ollegr [7]

Answer:

4,5,6 are the three consecutive numbers. 16, 25 and 36 are their squares.

Step-by-step explanation:

Let the three consecutive numbers be x, (x+1), (x+2)

Now, the squares of these three numbers are  x^{2} ,(x+1)^{2} ,(x+2)^{2}

Sum = 77

∴by the problem ,

x^{2} +(x+1)^{2}+(x+2)^{2}  = 77\\x^{2} +(x^{2} +2x+1)+(x^{2}+4x +4) = 77\\x^{2} +x^{2} +2x+1+x^{2} +4x +4 = 77\\3x^{2} +6x+5 = 77\\3x^{2} +6x = 77-5\\3x^{2} + 6x = 72\\3x^{2} +6x-72= 0\\

{Taking 3 common }

x^{2} +2x- 24 = 0\\

{By factorization}

x^{2} +2x- 24 =0\\ x^{2} +6x-4x-24=0\\x(x+6)-4(x+6)=0\\(x+6)(x-4)=0\\

Therfore,

x= -6,4\\

<em>X can't be negetive </em>

∴ x =4\\x+1=5\\x+2=6

The squares of the three consecutive numbers are 16, 25, 36

The three consecutive numbers whose sum is 77 are 4, 5, 6

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