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gavmur [86]
2 years ago
11

Solve: 4 In x = 2 In 25

Mathematics
2 answers:
mylen [45]2 years ago
7 0
Convert to log and then divide but it’s 12.5
valkas [14]2 years ago
3 0

Answer: it’s 5 just took it on edge

Step-by-step explanation:

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Compare the value of 3 in 302754 and 53891. The value of 3 in 302254 is _______ times the value of the 3 and 53891
noname [10]
Compare how many place values the 3's have.
The 3 in 302754 is in the 6th place value, while the 3 in 53891 is in the 4th place value. Each place value is 10 times the one below it. Since the first 3 is 2 place values ahead, 10*10=100 times.
8 0
3 years ago
Please help?!
Anton [14]

Answer:

Δ PQT ~ Δ QRS  .....{S-S-S test for similarity}...Proof is below.

Step-by-step explanation:

Given:

In Δ PQT

PQ = 30 ft

QT = 28 ft

TP = 20 ft

In Δ QRS

QR = 15 ft

RS = 14 ft

SQ = 10 ft

To Prove:

Δ PQT ~ Δ QRS

Proof:

First we consider  the ratio of the sides

\frac{PQ}{QR}=\frac{30}{15} = \frac{2}{1}            ..............( 1 )

\frac{QT}{RS}=\frac{28}{14} = \frac{2}{1}            ..............( 2 )

\frac{TP}{SQ}=\frac{20}{10} = \frac{2}{1}            ..............( 3 )

So By equation ( 1 ), ( 2 ) and  ( 3 ) we get

\frac{PQ}{QR}=\frac{QT}{RS} = \frac{TP}{SQ}

Now in Δ PQT  and Δ QRS we have

\frac{PQ}{QR}=\frac{QT}{RS} = \frac{TP}{SQ}

Which are corresponding sides of a similar triangle in proportion.

∴ Δ PQT ~ Δ QRS  .....{S-S-S test for similarity}...Proved

8 0
3 years ago
What happens when an image is reflected over y = -x
notka56 [123]

Answer:

Well, it's pretty simple. If your reflecting something over the y axis the X will change if it's negative or positive. So if it's -x and you flip it over it becomes a positive x. If you flip it over the x-axis the Y is the one that change to a negative or positive.

So if the shape flips over the y-axis, the X points will turn negative. for example, one of the points is (1,4) it will turn to (-1,4)

Step-by-step explanation:


7 0
3 years ago
Write an equation in slope-intercept form of the line that bisects the angle formed by BA and BC
slega [8]

Given:

Angled formed by ray BA and ray BC is 90 degrees.

To find:

The equation of line that bisects the angle formed by ray BA and ray BC.

Solution:

If a line bisects the angle formed by ray BA and ray BC, then it must be passes through point B and makes angles of 45 degrees with ray BA and ray BC.

It is possible if the line passes though point B(-1,3) and other point (-2,4).

Equation of line is

y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)

y-3=\dfrac{4-3}{-2-(-1)}(x-(-1))

y-3=\dfrac{1}{-1}(x+1)

y-3=-x-1

Add 3 on both sides.

y=-x-1+3

y=-x+2

Therefore, the required equation of line is y=-x+2.

8 0
3 years ago
Please help me solve this problem
olga2289 [7]
1,025. Multiply 55 by 15, then add the $200 fee. I hope this helps :)
7 0
2 years ago
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