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uranmaximum [27]
3 years ago
10

Multiply. Write the answer in standard form. (8+3i)2=

Mathematics
1 answer:
Flauer [41]3 years ago
6 0

Answer:

  55 +48i

Step-by-step explanation:

Complex numbers can be treated as though they were binomials with a variable "i". At the end, any instance of i² can be replaced by -1.

  (8 +3i)² = 8² + 2(8)(3i) +(3i)² = 64 +48i -9

  = 55 +48i

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<u>L</u><u>a</u><u>w</u><u> </u><u>o</u><u>f</u><u> </u><u>E</u><u>x</u><u>p</u><u>o</u><u>n</u><u>e</u><u>n</u><u>t</u>

\displaystyle \large{ {a}^{ - n}  =  \frac{1}{ {a}^{n} } }

Compare the terms.

\displaystyle \large{ {a}^{ - n}  =   {( - 2)}^{ - 3} }

Therefore, a = -2 and n = 3. From the law of exponent above, we receive:

\displaystyle \large{ {( - 2)}^{ - 3}  =  \frac{1}{ {( - 2)}^{ 3} } }

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Factor (-2)^3 out.

\displaystyle \large{ {( - 2)}^{ - 3}  =  \frac{1}{( - 2) \times ( - 2) \times ( - 2)}}

(-2) • (-2) = 4 | Negative × Negative = Positive.

\displaystyle \large{ {( - 2)}^{ - 3}  =  \frac{1}{4 \times ( - 2)}}

4 • (-2) = -8 | Negative Multiply Positive = Negative.

\displaystyle \large{ {( - 2)}^{ - 3}  =  \frac{1}{  - 8}}

If either denominator or numerator is in negative, it is the best to write in the middle or between numerator and denominators.

Hence,

\displaystyle \large \boxed{ {( - 2)}^{ - 3}  =  -  \frac{1}{  8}}

The answer is - 1 / 8

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The solution to the given equation is x = ±7. The correct option is d. x = ±7

<h3>Solving quadratic equations </h3>

From the question, we are to determine the solution to the given equation

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