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devlian [24]
3 years ago
10

How many sixteenths are there in 5/8​

Mathematics
1 answer:
nadya68 [22]3 years ago
6 0

Answer:

10!

Step-by-step explanation:

Exuse me if im wrong :')

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Three cards are drawn at random from a standard deck of cards, without replacement. Find the probability that the suits of the c
Evgesh-ka [11]

The probability that suits of cards are spades, hearts, and spades is 39/850 or 0.046.

According to the give question.

Three cards are drawn from a standard deck of cards without replacement.

Since,

The total number of cards in a standard deck = 52

Total number of spade cards = 13

Total number of heart cards = 13

Now,

The probabbility of getting first card as a spade card = 13/52 = 1/4

The probability of getting second card as heart card

= 13/(52 -1)     (cards are drawn without replacement)

= 13/51

The probability of getting third card as a spade card

= (13 - 1)/52 -2

= 12/50

= 6/25

Therefore, the probability that suits of the cards are spades, hearts, spades

= 1/4 × 13/51 × 6/25

= 39/850

= 0.046

Hence, the probability that suits of cards are spades, hearts, and spades is 39/850 or 0.046.

Find out more information about probability here:

brainly.com/question/11234923

#SPJ4

8 0
1 year ago
In parallelogram ABCD, ∠A and ∠B are adjacent. The measure of ∠B is twice the measure of ∠A. Which equation gives the exact meas
viktelen [127]
The right answer to this problem is B
4 0
3 years ago
Plz help I don’t under stand how to get this common ratio
Talja [164]

Answer:

2 over 5

Step-by-step explanation:

Common ratio =

7/ (35/2) = (14/2) / 7

Our answer became 2/5

7 0
3 years ago
Dan multiplied 1,563 by 4 and got the incorrect product of 2,252. Find the correct product and explain what Dan did wrong. Pleas
Morgarella [4.7K]

Answer:

The correct product is 6,252.

I don't know what Dan did wrong lol

8 0
2 years ago
Please solve the complex number by finding the complex conjugate.Correct answer will get brainliest!
jasenka [17]

-2 - 2i*square root of 11/483

6 0
2 years ago
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