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trapecia [35]
3 years ago
14

Which of the following best describes the term constructions in geometry?

Mathematics
1 answer:
hodyreva [135]3 years ago
4 0

The options in this question are missing; here is the complete question:

Which of the following best describes the term constructions in geometry?

A. Combining two or more figures together to create a new figure or shape.

B. A way to draw precise figures using a compass and a straightedge.

C. Creating a figure or shape by hand.

D. Places where things are being built that often slow down traffic.

The answer to this question is B. A way to draw precise figures using a compass and a straightedge.

Explanation:

Geometry is a sub-field of mathematics that studies figures, lines, angles, and related features. In this, the term "construction" describes the creation of figures by using a straight edge such as a ruler, a compass (object to draw circles or arcs and measure distances), and a pen, pencil, or similar instrument to draw. For example to draw or construct a circle a compass is mainly used while the construction of a hexagon requires a straight edge and compass. According to these ideas, the correct answer is B.

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Use the equation y = 7x to complete the table. What are the missing values of
Basile [38]

Answer:

D) When x=2, y=14
When x=4, y=28

Step-by-step explanation:

By using slope= y2-y1/x2-x1

I get (1,7) and (3,21) from the table

slope= 21-7/3-1= 14/2= 7

Then I plug in the values into y=mx+b

7= 7(1) +b

b= 0

Getting an equation of y=7x

When x= 2

y= 7(2)= 14

When x= 4

y= 7(4)= 28

7 0
3 years ago
A source of information randomly generates symbols from a four letter alphabet {w, x, y, z }. The probability of each symbol is
koban [17]

The expected length of code for one encoded symbol is

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha\ell_\alpha

where p_\alpha is the probability of picking the letter \alpha, and \ell_\alpha is the length of code needed to encode \alpha. p_\alpha is given to us, and we have

\begin{cases}\ell_w=1\\\ell_x=2\\\ell_y=\ell_z=3\end{cases}

so that we expect a contribution of

\dfrac12+\dfrac24+\dfrac{2\cdot3}8=\dfrac{11}8=1.375

bits to the code per encoded letter. For a string of length n, we would then expect E[L]=1.375n.

By definition of variance, we have

\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2

For a string consisting of one letter, we have

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha{\ell_\alpha}^2=\dfrac12+\dfrac{2^2}4+\dfrac{2\cdot3^2}8=\dfrac{15}4

so that the variance for the length such a string is

\dfrac{15}4-\left(\dfrac{11}8\right)^2=\dfrac{119}{64}\approx1.859

"squared" bits per encoded letter. For a string of length n, we would get \mathrm{Var}[L]=1.859n.

5 0
3 years ago
Anya wanted a book that cost $34.99 regularly at the bookstore. If Anya had a coupon for 20% off any regularly priced item at th
REY [17]

Answer:

$27.99

Step-by-step explanation:

34.99*.20 = 6.998

34.99-6.998 = 27.992

the answer rounded would be $27.99

Hope this helps

5 0
2 years ago
Read 2 more answers
Please help! Picture is listed
ss7ja [257]
AD is parallel to BC
5 0
3 years ago
Read 2 more answers
2. Determine the sum of the first 400 ODD numbers.<br><br>​
il63 [147K]

Odd numbers take the form 2n-1, where n\ge1 is an integer. When n=400, the last odd number would be 799. So we're adding

S=1+3+5+\cdots+795+797+799

By reversing the order of terms, we have

S=799+797+795+\cdots+5+3+1

and we can pair up terms in both sums at the same position to write

2S=(1+799)+(3+797)+(5+795)+\cdots(795+5)+(797+3)+(799+1)

so that we are basically adding 400 copies of 800, and from there we can find the value of the sum right away:

2S=400\cdot800\implies S=160,000

###

We could also make use of the formulas,

\displaystyle\sum_{i=1}^n1=n

\displaystyle\sum_{i=1}^ni=\dfrac{n(n+1)}2

We have

S=\displaystyle\sum_{i=1}^{400}(2i-1)=2\sum_{i=1}^{400}i-\sum_{i=1}^{400}1=400(400+1)-400=400^2=160,000

3 0
3 years ago
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