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MAXImum [283]
3 years ago
15

Help me people I need it

Mathematics
1 answer:
Aleks04 [339]3 years ago
6 0
You would put up as a fraction and solve it
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F(x)=-x^2+19<br><br> Find f(3)
Arturiano [62]

Answer:

f(3) = 10

Step-by-step explanation:

f(x)=-x^2+19

Let x= 3

f(x)=- (3)^2+19

    = -9 + 19

    = 10

8 0
3 years ago
Read 2 more answers
Eric is designing a logo for a company. The logo consists of two identical parallelograms joined at their longest sides. One of
Sati [7]

Answer:

A=3.125\ cm^2

Step-by-step explanation:

Given that,

The base of the parallelogram, b = 2.5 cm

Height of the parallelogram, h = 1.25 cm

We need to find the area of the logo. The formula for the area of the parallelogram is given by :

A=b\times h\\\\A=2.5\times 1.25\\A=3.125\ cm^2

So, the area of the logo is 3.125\ cm^2.

8 0
4 years ago
A box in a supply room contains 24 compact fluorescent lightbulbs, of which 8 are rated 13-watt, 9 are rated 18-watt, and 7 are
Marrrta [24]

Answer:

a) There is 17.64% probability that exactly two of the selected bulbs are rated 23-watt.

b) There is a 8.65% probability that all three of the bulbs have the same rating.

c) There is a 12.45% probability that one bulb of each type is selected.

Step-by-step explanation:

There are 24 compact fluorescent lightbulbs in the box, of which:

8 are rated 13-watt

9 are rated 18-watt

7 are rated 23-watt

(a) What is the probability that exactly two of the selected bulbs are rated 23-watt?

There are 7 rated 23-watt among 23. There are no replacements(so the denominators in the multiplication decrease). Then can be chosen in different orders, so we have to permutate.

It is a permutation of 3(bulbs selected) with 2(23-watt) and 1(13 or 18 watt) repetitions. So

P = p^{3}_{2,1}*\frac{7}{24}*\frac{6}{23}*\frac{17}{22} = \frac{3!}{2!1!}*\frac{7}{24}*\frac{6}{23}*\frac{17}{22} = 3*\frac{7}{24}*\frac{6}{23}*\frac{17}{22} = 0.1764

There is 17.64% probability that exactly two of the selected bulbs are rated 23-watt.

(b) What is the probability that all three of the bulbs have the same rating?

P = P_{1} + P_{2} + P_{3}

P_{1} is the probability that all three of them are 13-watt. So:

P_{1} = \frac{8}{24}*\frac{7}{23}*\frac{6}{22} = 0.0277

P_{2} is the probability that all three of them are 18-watt. So:

P_{2} = \frac{9}{24}*\frac{8}{23}*\frac{7}{22} = 0.0415

P_{3} is the probability that all three of them are 23-watt. So:

P_{3} = \frac{7}{24}*\frac{6}{23}*\frac{5}{22} = 0.0173

P = P_{1} + P_{2} + P_{3} = 0.0277 + 0.0415 + 0.0173 = 0.0865

There is a 8.65% probability that all three of the bulbs have the same rating.

(c) What is the probability that one bulb of each type is selected?

We have to permutate, permutation of 3(bulbs), with (1,1,1) repetitions(one for each type). So

P = p^{3}_{1,1,1}*\frac{8}{24}*\frac{9}{23}*\frac{7}{22} = 3**\frac{8}{24}*\frac{9}{23}*\frac{7}{22} = 0.1245

There is a 12.45% probability that one bulb of each type is selected.

3 0
3 years ago
Word problem for 456 divided by 6
musickatia [10]

Answer:

76

Step-by-step explanation:

456 divided by 6 equals 76. Hope that helps.

8 0
3 years ago
Read 2 more answers
use a mental math strategy to find 4,290+3,602. explain how to check your answer using a different strategy.
Marianna [84]
=7,892 , you could write out your numbers, then line them up to then add them.
5 0
3 years ago
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