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3 years ago

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The class has collected $75.50 for a pizza party. A large pizza costs $9.50. Which one-step-inequality could be used to find the

maximum number of pizza’s the class can buy without exceeding their maximum?

1 answer:

Veseljchak [2.6K]3 years ago

4 0

Answer:

7 large pizzas

Step-by-step explanation:

multiply 9.50 by every number on the calculator and get 9.50×7=66.5

or just divide 75.50 by 9.50

or idk

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Given: measure of angle KJ = 124°, measure of IC =38°<br><br> Find: m∠CQJ, m∠LIJ.

VLD [36.1K]

Answer:

Part 1) $m$

Part 2) $m$

Step-by-step explanation:

Part 1) Find the measure of angle CQJ

we know that

The measure of the interior angle is the semi-sum of the arcs comprising it and its opposite.

$m$

$arc\ IK+arc\ CJ=360\°-(arc\ IC+arc\ KJ)$

substitute the values

$arc\ IK+arc\ CJ=360\°-(38\°+124\°)=198\°$

$m$

Part 2) Find the measure of angle LIJ

step 1

Find the measure of angle IJL

we know that

The inscribed angle is half that of the arc it comprises.

$m$

substitute the values

$m$

step 2

Find the measure of angle ILJ

we know that

The measurement of the external angle is the semi-difference of the arcs it encompasses.

$m$

substitute the values

$m$

step 3

Find the measure of angle LIJ

Remember that the sum of the interior angles of a triangle must be equal to 180 degrees

In the triangle LIJ

$m$

substitute the values

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$m$

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3 years ago

HEEEEEEEELLLLPPPP PLLLLAZZZZZZZZZ

OverLord2011 [107]

Answer:

The first picture is B and the second one is (0,-3)

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2 years ago

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Find the equation, (f(x) = a(x - h)2 + k), for a parabola containing point (2, -1) and having (4, -3) as a vertex. What is the s

Nataliya [291]

Answer:

$f(x)=\frac{1}{2}x^2-4x+5$

Step-by-step explanation:

A parabola is written in the form

$f(x)=a((x-h)^2+k)$ (1)

where:

$h$ is the x-coordinate of the vertex of the parabola

$ak$ is the y-coordinate of the vertex of the parabola

$a$ is a scale factor

For the parabola in the problem, we know that the vertex has coordinates (4,-3), so we have:

$h=4$ (2)

$ak=-3$

From this last equation, we get that $a=\frac{-3}{k}$ (3)

Substituting (2) and (3) into (1) we get the new expression:

$f(x)=-\frac{3}{k}((x-4)^2+k) = -\frac{3}{k}(x-4)^2 -3$ (4)

We also know that the parabola contains the point (2,-1), so we can substitute

x = 2

f(x) = -1

Into eq.(4) and find the value of k:

$-1=-\frac{3}{k}(2-4)^2-3\\-1=-\frac{3}{k}\cdot 4 -3\\2=-\frac{12}{k}\\k=-\frac{12}{2}=-6$

So we also get:

$a=-\frac{3}{k}=-\frac{3}{-6}=\frac{1}{2}$

So the equation of the parabola is:

$f(x)=\frac{1}{2}((x-4)^2 -6)$ (5)

Now we want to rewrite it in the standard form, i.e. in the form

$f(x)=ax^2+bx+c$

To do that, we simply rewrite (5) expliciting the various terms, we find:

$f(x)=\frac{1}{2}((x^2-8x+16)-6)=\frac{1}{2}(x^2-8x+10)=\frac{1}{2}x^2-4x+5$

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2 years ago

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Answer:

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Step-by-step explanation:

Since we have 1 crate and 8 boxes fit into one crate.

So, volume of one crate, V' = 8 × volume of 1 box, V

Since the box is a rectangular prism of sides 2512 inches high, 18 inches long, and 18 inches wide, its volume, V = lwh where l = length of prism, h = height of prism and w = width of prism.

So, V = lwh = 18 in × 18 in × 2512 in = 813 888 in³

So, V' = 8 × 813 888 in³ = 6 511 104 in³

So, the minimum volume of the crate is 6 511 104 in³

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2 years ago

Given f(x) = 10-2x find f(7)

lara [203]

10 - 2x
10 - 2(7)
= 10 - 14
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