4 cos² x - 3 = 0
4 cos² x = 3
cos² x = 3/4
cos x = ±(√3)/2
Fixing the squared cosine doesn't discriminate among quadrants. There's one in every quadrant
cos x = ± cos(π/6)
Let's do plus first. In general, cos x = cos a has solutions x = ±a + 2πk integer k
cos x = cos(π/6)
x = ±π/6 + 2πk
Minus next.
cos x = -cos(π/6)
cos x = cos(π - π/6)
cos x = cos(5π/6)
x = ±5π/6 + 2πk
We'll write all our solutions as
x = { -5π/6, -π/6, π/6, 5π/6 } + 2πk integer k
Answer:
Step-by-step explanation:
A. Directrix: y = 4-6 = -2
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B. Axis of symmetry: x = 6
Axis of symmetry intersects directrix at (6,-2)
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C . Vertex is halfway between focus and directrix, at (6,1)
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D. The focus lies above the directrix, so the parabola opens upwards.
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E. Focal length p = 1/(4×0.5)
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F. p = 0.5
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G. y = 0.5(x-6)² + 1
Answer:
Um what is the question on the test?
9514 1404 393
Answer:
-2/5
Step-by-step explanation:
The slopes of parallel lines are the same. The slope of the given line is -2/5, the coefficient of x.
The slope of a parallel line is -2/5.
Check image below for answer!
