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vlabodo [156]
3 years ago
10

A trapezoid has an area of 24 square meters. The lengths of the bases of the trapezoid are 5 meters and 7 meters. What is the he

ight of the trapezoid?
4 meters
144 meters
2 meters
1 meter
Mathematics
2 answers:
viva [34]3 years ago
7 0

Answer:

The answer is 4 meters. (A)

Step-by-step explanation:


Maurinko [17]3 years ago
3 0

The area of any trapezoid is

                      Area = (1/2) x (height) x (one base + the other base) .

Take that formula and write in the numbers you know:

                 (24 m²) = (1/2) x (height) x (5m + 7m)

                 (24 m²) =  (6m) x (height)

Divide each side by  6m :

                 Height = (24 m² / 6m) 

                            =     4 m .

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A one-parameter family of solutions of the de p' = p(1 − p) is given below.
tensa zangetsu [6.8K]

Answer:

A solution curve pass through the point (0,4) when c_{1} = -\frac{4}{3}.

There is not a solution curve passing through the point(0,1).

Step-by-step explanation:

We have the following solution:

P(t) = \frac{c_{1}e^{t}}{1 + c_{1}e^{t}}

Does any solution curve pass through the point (0, 4)?

We have to see if P = 4 when t = 0.

P(t) = \frac{c_{1}e^{t}}{1 + c_{1}e^{t}}

4 = \frac{c_{1}}{1 + c_{1}}

4 + 4c_{1} = c_{1}

c_{1} = -\frac{4}{3}

A solution curve pass through the point (0,4) when c_{1} = -\frac{4}{3}.

Through the point (0, 1)?

Same thing as above

P(t) = \frac{c_{1}e^{t}}{1 + c_{1}e^{t}}

1 = \frac{c_{1}}{1 + c_{1}}

1 + c_{1} = c_{1}

0c_{1} = 1

No solution.

So there is not a solution curve passing through the point(0,1).

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3 years ago
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Step-by-step explanation:

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check attachment

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