Answer: 29
Step-by-step explanation:
29 ÷ 8 = 3 remainder: 5
I solved using long division.
Plit the second term in 2{x}^{2}-x-12x2 −x−1 into two terms2{x}^{2}+x-2x-1=02x2 +x−2x−1=0
2 Factor out common terms in the first two terms, then in the last two termsx(2x+1)-(2x+1)=0x(2x+1)−(2x+1)=0
3 Factor out the common term 2x+12x+1(2x+1)(x-1)=0(2x+1)(x−1)=0
4 Solve for xxx=-\frac{1}{2},1x=−21 ,1
Decimal Form: -0.5, 1
3x^2-6x+5
for ax^2+bx+c=0
discriminant is b^2-4ac
when
1. b^2-4ac>0, there are 2 real roots
2. b^2-4ac=0, there is 1 real root
3. b^2-4ac<0, there are 2 complex roots
3x^2-6x+5
a=3
b=-6
c=5
(-6)^2-4(3)(5)
36-60
-24
answer is -24 is the discriminant
