Answer:
x= 4 and y= 11
Step-by-step explanation:
The problem to solve is:
y = 2x + 3 (equation 1)
y = 3x - 1 (equation 2)
Since y = 3x - 1 Solve x from equalution 1
3x - 1 = 2x + 3
3x - 2x = 3 + 1
x = 4
Since x is 4, solve for y
y = 3x - 1
y = 3(4) - 1
y = 12 -1
y = 11
x =4 and y =7
(x^a)(x^b)=x^(a+b)
(ab)(cd)=(a)(b)(c)(d)
x^-m=1/(x^m)
(3y^-4)(2y^-4)=
(3)(y^-4)(2)(y^-4)=
(6)(y^-8)=
6/(y^8)
Answer: -12.8x-20y+8.4
Step-by-step explanation: I multiplied the numbers in parentheses by 4.
Answer:
sinx
Step-by-step explanation:
hello :
note :
for all x in ℝ : 1) sin(x+2π) = sinx 2) sin(π-x) = sinx
in this exercice :
3π - x = 2π+(π - x)
sin(3π - x) = sin(2π +(π - x)) =sin(π-x) = sinx
C, always go with supervisors