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grigory [225]
3 years ago
11

What is the least common denominator for adding the fractions 4/15, 1/12, and 3/8

Mathematics
2 answers:
il63 [147K]3 years ago
5 0
I think you want the least common multipule (exg LCM of 2,3,4 is 12)

so we find the factors and include all of them so like this

15=3 times 5
12=2 times 2 times 3
8=2 times 2 times 2

so to include all of them we include 3 2's, 1 3 and 1 5 or 2 times 2 times 2 times 3 times 5 or 8 times 15 or 4 times 30 or 120

the LCM is 120

so 4/15=32/120
1/12=10/120
3/8=45/120

add 32/120+10/120+45/120=(32+10+45)/120=87/120
sladkih [1.3K]3 years ago
3 0
The least common denominator would be the least common multiple (LCM) of the denominators, 15 12 and 8.

To find the LCM, multiply two of the numbers together and test to see if the third one divides evenly into it.

15 x 8 = 120

120 ÷ 12 = 10

Because all three numbers go evenly into 120 (and 120 is the smallest number for which that is true), the least common denominator would be 120.
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First find the area of the whole square. Even the part that isn't part of the area. Then find the area of the spots that aren't part of the shape. Then subtract that area from the area of the whole thing.

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270-128=142

Area= 142ft^2
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2х + Зу = -8<br> 2х + Зу = 5<br> Solve and Explain how please
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6 0
3 years ago
The parabola with equation $y=ax^2+bx+c$ is graphed below:
Mashutka [201]

Answer:

m-n=2

Step-by-step explanation:

Instead of using the standard form, we can use the vertex form of a quadratic equation:

f(x)=a(x-h)^2+k

Where a is the leading coefficient, and (h, k) is our vertex.

Our vertex point is at (2, -4). So, let’s substitute 2 for h and -4 for k:

f(x)=a(x-2)^2-4

Now, we need to determine a.

We know that it passes through the point (4, 12). So, when x is 4, y must be 12. In other words:

12=a((4)-2)^2-4

Solve for a. Subtract within the parentheses:

12=a(2)^2-4

Add 4 to both sides:

16=a(2)^2

Square:

16=4a

Solve:

a=4

Thererfore, the value of a is 4.

So, our function is:

f(x)=4(x-2)^2-4

Now, let’s find our roots. Set the equation to 0 and solve for x:

0=4(x-2)^2-4

4=4(x-2)^2\\1=(x-2)^2\\x-2=\pm1 \\ x=2\pm1 \\ x=3\text{ or } 1

So, our roots are 1 and 3.

The greater root is 3 and the lesser root is 1.

Therefore, m-n, where m>n, is 3-1 or 2.

Our final answer is 2.

4 0
3 years ago
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