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alisha [4.7K]
3 years ago
15

Oliver draws a line on his paper and from a point on the line draws a circle. He then measures the radius of his circle and cons

tructs an arc inside his circle from a point on the circle. What is he trying to construct?
A) a square inscribed in a circle
B) a trapezoid inscribe in a circle
C) a pentagon inscribed in a circle
D) an equilateral triangle inscribed in a circle
Mathematics
2 answers:
Olenka [21]3 years ago
5 0
The correct answer would be D., a a right triangle inscribed inside a circle. I just barely did what the instructions said, and it was right. :P
I hope you find this helpful, feel free to mark as brainliest, and good luck! (:
Tresset [83]3 years ago
4 0

Answer:

D). an equilateral triangle inscribed in a circle

Step-by-step explanation:

Oliver draws a line on a paper and from a point on the line draws  a circle. He then measures the radius of the circle and constructs an arc on the circle from the point on the circumference where the radius meets. This gives a chord because on joining the point where the arc coincides on the circumference and the point where the radius meets the circumference gives you a chord which is equal to the radius of the circle.

       Then join the arc from the center of the circle which gives us a equilateral triangle of equal sides which is equal to the radius of the triangle.

Hence, option D is correct.

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What is the product of all constants $k$ such that the quadratic $x^2 + kx +15$ can be factored in the form $(x+a)(x+b)$, where
Setler79 [48]

Answer:

k=-16,k=-8,k=8,k=16

Step-by-step explanation:

We are given quadratic equations as

x^2+kx+15

and it can be factored as

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now, we can multiply factor term

(x+a)(x+b)=x^2+(a+b)x+ab

now, we can compare

x^2+(a+b)x+ab=x^2+kx+15

so, we get

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we are given that

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so, we can find all possible factors

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15=(-3\times -5),(3\times 5)

so, we can find k

At (-1\times -15):

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we can plug values

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At (1\times 15):

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At (-3\times -5):

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k=-3-5

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At (3\times 5):

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we can plug values

k=3+5

k=8

So, values of k are

k=-16,k=-8,k=8,k=16

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