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3 years ago

14

Line CD passes through points C(3, –5) and D(6, 0). What is the equation of line CD in standard form?

2 answers:

GrogVix [38]3 years ago

8 0

$\bf C(\stackrel{x_1}{3}~,~\stackrel{y_1}{-5})\qquad 
D(\stackrel{x_2}{6}~,~\stackrel{y_2}{0})
\\\\\\
% slope = m
slope = m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{0-(-5)}{6-3}\implies \cfrac{0+5}{6-3}\implies \cfrac{5}{3}
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-5)=\cfrac{5}{3}(x-3)\implies y+5=\cfrac{5}{3}x-5
\\\\\\
y=\cfrac{5}{3}x-10\implies \stackrel{standard~form}{-\cfrac{5}{3}x+y=-10}$

disa [49]3 years ago

6 0

Just see my atachment.

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The solution of the given trigonometric equation

$x = \frac{\pi }{6}$

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