All categories

3 years ago

Line CD passes through points C(3, –5) and D(6, 0). What is the equation of line CD in standard form?

Mathematics

2 answers:

GrogVix [38]3 years ago

8 0

$\bf C(\stackrel{x_1}{3}~,~\stackrel{y_1}{-5})\qquad 
D(\stackrel{x_2}{6}~,~\stackrel{y_2}{0})
\\\\\\
% slope = m
slope = m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{0-(-5)}{6-3}\implies \cfrac{0+5}{6-3}\implies \cfrac{5}{3}
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-5)=\cfrac{5}{3}(x-3)\implies y+5=\cfrac{5}{3}x-5
\\\\\\
y=\cfrac{5}{3}x-10\implies \stackrel{standard~form}{-\cfrac{5}{3}x+y=-10}$

disa [49]3 years ago

6 0

Just see my atachment.

You might be interested in

Pls help me in these two little exercises about the slope.

den301095 [7]

Answer:

3) $y=\dfrac35x+\dfrac25$

4) a) $y=-2x+7$

b) $y=\dfrac12x+\dfrac92$

Step-by-step explanation:

Exercise 3

$-3x + 5y = 2$

$\implies 5y = 3x + 2$

$\implies y=\dfrac35x+\dfrac25$

Exercise 4

a) If L2 is parallel to L1, it has the same slope (gradient) ⇒ $m = -2$

If L2 passes through point (3, 1):

$y-y_1=m(x-x_1)$

$\implies y-1=-2(x-3)$

$\implies y=-2x+7$

So L2 = L1

b) If L3 is perpendicular to L1, then the slope of L3 is the negative reciprocals of the slope of L1 ⇒ $m = \dfrac12$

If L3 passes through point (-5, 2):

$y-y_1=m(x-x_1)$

$\implies y-2=\dfrac12(x+5)$

$\implies y=\dfrac12x+\dfrac92$

4 0

2 years ago

Read 2 more answers

Solve the equation for x √x+4-7=1 Options: x=4 x=12 x=60 x=68

KIM [24]

Answer:

i honestly dont know its tooooo hard

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

How can i know where to place the first digit of a quotient

Leno4ka [110]

Place it in front of the second digit hopefully that helps I'm sorry I'm really tired

5 0

3 years ago

What are shaped that can classify with these

ella [17]

Answer:A.) triangular prism B.) triangular-based pyramid

Step-by-step explanation:

5 0

4 years ago

In sunlight, a vertical stick has a height of 5 ft and casts a shadow 3 ft long at the same time that a nearby tree casts a shad

leva [86]

The tree is 25 feet tall. Given the height of the stick and the shadow it cast, the angle formed by the sun and the stick's height can be obtained by taking the Inverse Tangent of 3/5. This is equal to 30.93. This angle is equal to the angle formed by the sun and the tree's height. Using the tangent formula, Tan (30.93)=tree's shadow (15 ft)/ height of the tree, giving the answer 25 feet.

7 0

3 years ago

Read 2 more answers