Question

The populations and land areas of four cities in Texas are shown.

Answer 1

The ratio for population density is population:area

Using this, we find that choices 1, 4, and 5 are true,

:)

Answer 2

we know that

The population density is the number of people living in each unit of area. Is equal to the population divided by the total area.

so

Let

x------> population (number of people)

y------>the area in $Km^{2}$

z-----> the population density

$z=\frac{x}{y}$

Find the population density of the cities

City A

$z=\frac{2,195,914}{1,553}=1,413.98\frac{people}{Km^{2}}$

City B

$z=\frac{48,592}{26}=1,868.92\frac{people}{Km^{2}}$

City C

$z=\frac{1,257,676}{999}=1,258.93\frac{people}{Km^{2}}$

City D

$z=\frac{196,429}{258}=761.35\frac{people}{Km^{2}}$

Statements

case A) The population density for City B can be found using the ratio $48,592 : 26$

The statement is true -------> see the procedure

case B) The population density for City D can be found using the ratio $258 : 196,429$

The statement is False

Because, the population density for City D can be found using the ratio $196,429 : 258$ ----> see the procedure

case C) City A has the greatest population density of the four cities

The statement is False

Because, the greatest population density of the four cities is the city B (see the procedure)

case D) The population density of City B is greater than that of City C

The statement is True -----> see the procedure

the greatest population density of the four cities is the city B

case E) City D has the lowest population density of the four cities

The statement Is True -------> see the procedure