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Mazyrski [523]
3 years ago
14

100 to 150. What is the percent of change?

Mathematics
2 answers:
jok3333 [9.3K]3 years ago
3 0

We have to find the percentage change from 100 to 150.

To find percentage we have to subtract the small number from the greater and number and divide it with the original number and then multiply it with 100.

Here subtracting the smaller from greater, we will get,

(150-100) = 50

Now the percentage of change is,

(\frac{50}{100} )(100)%

\frac{(50)(100)}{100}%

\frac{5000}{100}%

50%

We have got the required answer. The percentage of change is 50%.

miv72 [106K]3 years ago
3 0

Percent change = [(100 - 150) / 100] x 100 = 50 % (increase) so basically just 50! (Hope this helps!)
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2.5 x (9+12) = 52.5

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14is 10% of what number
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8 0
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50 points! I understand A. and B. but I would really appreciate help with C.
FromTheMoon [43]

Answer:

51.72\text{ cells per hour}

Step-by-step explanation:

So, the function, P(t), represents the number of cells after t hours.

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C)

So, we are given that the quadratic curve of the trend is the function:

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Expand:

P'(t)=\frac{d}{dt}[6.10t^2]+\frac{d}{dt}[-9.28t]+\frac{d}{dt}[16.43]

Move the constant to the front using the constant multiple rule. The derivative of a constant is 0. So:

P'(t)=6.10\frac{d}{dt}[t^2]-9.28\frac{d}{dt}[t]

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Simplify:

P'(t)=12.20t-9.28

So, to find the instantaneous rate of growth at t=5, substitute 5 into our differentiated function:

P'(5)=12.20(5)-9.28

Multiply:

P'(5)=61-9.28

Subtract:

P'(5)=51.72

This tells us that at <em>exactly</em> t=5, the rate of growth is 51.72 cells per hour.

And we're done!

7 0
2 years ago
Of the 130 students distance learning math with Mr. Bischof, 63% of them actually work through the material. Approximately, how
QveST [7]

Answer:

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because 63% of 130 is 81.9

and since the question is asking approximately which means rounding, so you round 81.9 to get 82.  

7 0
3 years ago
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