Answer: ![\begin{bmatrix}\mathrm{Solution:}\:&\:x\le \frac{17}{3}\:\\ \:\mathrm{Decimal:}&\:x\le \:5.66666\dots \\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:\frac{17}{3}]\end{bmatrix}](https://tex.z-dn.net/?f=%5Cbegin%7Bbmatrix%7D%5Cmathrm%7BSolution%3A%7D%5C%3A%26%5C%3Ax%5Cle%20%5Cfrac%7B17%7D%7B3%7D%5C%3A%5C%5C%20%5C%3A%5Cmathrm%7BDecimal%3A%7D%26%5C%3Ax%5Cle%20%5C%3A5.66666%5Cdots%20%5C%5C%20%5C%3A%5Cmathrm%7BInterval%5C%3ANotation%3A%7D%26%5C%3A%28-%5Cinfty%20%5C%3A%2C%5C%3A%5Cfrac%7B17%7D%7B3%7D%5D%5Cend%7Bbmatrix%7D)
Step-by-step explanation:
<span>1. </span>When given a raw score, it must be converted
into a z-score (standard score). Raw scores cannot be placed on a normal
distribution curve because they do not have the same means and standard
deviations, but when it is converted into a z-score, the number of standard
deviations above or below the population mean can be measured. The z-scores on
the center are average, the scores on the left are lower than average and the
scores on the right are higher than average.
<span>2. </span>A z-score is a standard score which can be
placed on a normal distribution curve. A z-score indicates the distance of the
standard deviations from the mean (center of the curve).
About 1.76 percent
I did the math myself
Answer:
16/100
Step-by-step explanation:
the decimal is 16 hundreths of one
