Answer:
Perimeter: 4 * s
Area: S 2
Diagonal: s 2 \sqrt {2} 2
Area of square when diagonal is given = 1 2 × d 2 \frac {1} {2}\times d^ {2} 21 × d2
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
A is the correct answer because the equation matches option A.
(-2 1/2) + (-3 1/4)
The minus sign in -2 1/2 shows that the submarine descended and then descended again with the addition sign. Though the addition sign can mean that it ascended its incorrect.
With the equation in hand, we can prove that option A is correct.
If the submarine descended 2 1/2 miles then here must be a minus sign next to the 2 1/2. But if it ascended then there would've been an addition sign to show that it ascended. The other value - 3 1/4 also shows that it ascended with the help of the addition sign.
Ascends - values increase from smallest to highest.
Descends - values decrease from highest to smallest.
Answer:
For A = 32/5 and B = 8 the system of equations will have infinitely many solutions.
Step-by-step explanation:
Given equations are:
4x + 5y = 10
Ax + By = 16
The general form of linear equation in two variables is given by:
Here a, b and c are constants and x,y are variables.
In the given equations, after comparing with the general form
"In order for a system of equations to have infinity many solutions,
"
Putting the values we get
Hence,
For A = 32/5 and B = 8 the system of equations will have infinitely many solutions.
Answer:5
Step-by-step explanation:
Since Michelle (he ? ) has 11/12 quarts of paint, and need 1/6 per quart to paint, we do 11/12 / 1/6 = 11/2, or 5.5. We cannot paint .5 of a block, so Michelle can only paint 5 quarts.
Splitting up the interval of integration into 
subintervals gives the partition
![\left[0,\dfrac1n\right],\left[\dfrac1n,\dfrac2n\right],\ldots,\left[\dfrac{n-1}n,1\right]](https://tex.z-dn.net/?f=%5Cleft%5B0%2C%5Cdfrac1n%5Cright%5D%2C%5Cleft%5B%5Cdfrac1n%2C%5Cdfrac2n%5Cright%5D%2C%5Cldots%2C%5Cleft%5B%5Cdfrac%7Bn-1%7Dn%2C1%5Cright%5D)
Each subinterval has length 
. The right endpoints of each subinterval follow the sequence
with 
. Then the left-endpoint Riemann sum that approximates the definite integral is
and taking the limit as 
gives the area exactly. We have
