earthworms he can have if his square of compost has a side length that is 3 times longer .
<u>Step-by-step explanation:</u>
Here we have , Hiram raises earthworms. in a square of compost 4ft by 4ft he can have 1000 earthworms. We need to find how many earthworms can he have if his square of compost has a side length that is 3 times longer .
Area of square compost = ![side^2](https://tex.z-dn.net/?f=side%5E2)
⇒ ![Area = side^2](https://tex.z-dn.net/?f=Area%20%3D%20side%5E2)
⇒ ![Area = 4^2](https://tex.z-dn.net/?f=Area%20%3D%204%5E2)
⇒
In this , square compost with
can have 1000 earthworms ! if side is 3 times longer i.e. New side =
, So , new area will be :
⇒
⇒ ![Area = 9side^2](https://tex.z-dn.net/?f=Area%20%3D%209side%5E2)
⇒![Area =9(16)](https://tex.z-dn.net/?f=Area%20%3D9%2816%29)
⇒![Area = 144ft^2](https://tex.z-dn.net/?f=Area%20%3D%20144ft%5E2)
Now ,
can have 1000 earthworms ,So
will have :
⇒![\frac{1000(144)}{16}](https://tex.z-dn.net/?f=%5Cfrac%7B1000%28144%29%7D%7B16%7D)
⇒ ![9000](https://tex.z-dn.net/?f=9000)
Therefore,
earthworms he can have if his square of compost has a side length that is 3 times longer .