Question

Hiram raises earthworms. in a square of compost 4ft by 4ft he can have 1000 earthworms. how many earthworms can he have if his square of compost has a side length that is 3 times longer

Answer 1

$9000$ earthworms he can have if his square of compost has a side length that is 3 times longer .

Step-by-step explanation:

Here we have , Hiram raises earthworms. in a square of compost 4ft by 4ft he can have 1000 earthworms. We need to find how many earthworms can he have if his square of compost has a side length that is 3 times longer .

Area of square compost = $side^2$

⇒ $Area = side^2$

⇒ $Area = 4^2$

⇒ $Area = 16ft^2$

In this , square compost with $Area = 16ft^2$ can have 1000 earthworms ! if side is 3 times longer i.e. New side = $3(side)$ , So , new area will be :

⇒$Area = (3side)^2$

⇒ $Area = 9side^2$

⇒$Area =9(16)$

⇒$Area = 144ft^2$

Now , $Area = 16ft^2$ can have 1000 earthworms ,So $Area = 144ft^2$ will have :

⇒$\frac{1000(144)}{16}$

⇒ $9000$

Therefore, $9000$ earthworms he can have if his square of compost has a side length that is 3 times longer .