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4 years ago

Round the number to the nearest thousand Add 27,498 + 4,657

Mathematics

2 answers:

erastovalidia [21]4 years ago

7 0

Answer:

32000

Step-by-step explanation:

If you add 27,498 + 4,657 you will get 32,155 if you count the positions by 5 = ones 5 = tens 1 = hundreds 2 = Thousands, now what you want to do is focus on the numbers below 2 thousand 3<u>2,155</u> now look over to the hundreds place you can see that there is a 1 there and if a number that is not higher than 5 it will not round up to the higher number let's say we had 75 cookies and we needed to round it to the nearest tens since we have a 5 it will be 80 cookies. So then you would round it to 32,000. You may be wondering why there are 0s and not the numbers? After you round the number you need to reset the numbers/value below it to 0.

Lyrx [107]4 years ago

3 0

Answer:

32000

Step-by-step explanation:

We need to add before we round

27,498 + 4,657

I like to line it up vertically

27,498

+ 4,657

-------------------

32,155

We are rounding to the nearest thousand

We are rounding the 2 so we look at the 1

1<5 so we will leave the 2 alone

32155 rounds to 32000

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The answers are

1. $1$

2. $\frac{5}{8}$

3. $\frac{19}{5}$

What are fractions?

Any number of equal parts is represented by a fraction, which also represents a portion of a whole. In ordinary English, a fraction refers to the number of parts of a specific size.

We are given,

1. $\frac{4}{7} + \frac{3}{7}$

As the denominator of both fractions are same we add the numerator

We get,

$\frac{7}{7}=1$

2. $\frac{7}{8}-\frac{2}{8}$

As the denominator of both the fractions are same we subtract the value in the numerator we get,

$\frac{7}{8}-\frac{2}{8}=$ $\frac{5}{8}$

3. $6\frac{4}{5}-3$

We first simplify the first term of the equation,

$6\frac{4}{5}=\frac{34}{5}$

Now as the denominator is not same we use cross multiplication to perform the operation

$\frac{34}{5}-3=\frac{34-15}{5}$

On further simplifying we get,

$\frac{34-15}{5}=\frac{19}{5}$

Hence the answers are

1. 1

2. $\frac{5}{8}$

3. $\frac{19}{5}$

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You roll two six-sided dice. Match each event with its probability.

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Answer:

A) probability the sum is 8 or 11= 4/21

B) probability that sum is 12 or less than 10 = 6/7

C) Probability that the sum is 3 or less than 3 = 2/21

D) Probability that the sum is 2 or 10 = 1/7

Step-by-step explanation:

Since we have the same probability of each event in each dice, the answer would be just to check the different outcomes, two dices, each with 1 to 6;

(1,1);(1,2);(1,3);(1,4);(1,5);(1,6);(2,2);(2,3);(2,4);(2,5);(2,6);(3,3);(3,4);(3,5);(3,6);(4,4);(4,5);(4,6);(5,5);(5,6);(6,6)

Thus, there are 21 possible outcomes.

Now,

A) probability that the sum is 8 or 11;

From the outcomes above, the number of outcomes that have a sum as 8 or 11 are;

(2,6) ; (3,5) ; (4,4) ; (5,6)

So,probability = 4/21

B) From the outcomes above, the number of outcomes that are 12 or less than 10 are;

(1,1);(1,2);(1,3);(1,4);(1,5);(1,6);(2,2);(2,3);(2,4);(2,5);(2,6);(3,3);(3,4);(3,5);(3,6);(4,4);(4,5);(6,6).

There are 18 possible outcomes.

So, probability that sum is 12 or less than 10 = 18/21 = 6/7

C)From the initial 21 outcomes, the number of outcomes that the sum is 3 or less than 3 are;(1,1);(1,2)

Thus,

Probability that the sum is 3 or less than 3 = 2/21

D) From the initial 21 outcomes, the number of outcomes that the sum is 2 or 10 are;

(1,1); (4,6) ; (5,5)

Thus,

Probability that the sum is 2 or 10 = 3/21 = 1/7

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