Round the number to the nearest thousand Add 27,498 + 4,657

Mathematics

2 answers:

erastovalidia [21]3 years ago

7 0

Answer:

32000

Step-by-step explanation:

If you add 27,498 + 4,657 you will get 32,155 if you count the positions by 5 = ones 5 = tens 1 = hundreds 2 = Thousands, now what you want to do is focus on the numbers below 2 thousand 3<u>2,155</u> now look over to the hundreds place you can see that there is a 1 there and if a number that is not higher than 5 it will not round up to the higher number let's say we had 75 cookies and we needed to round it to the nearest tens since we have a 5 it will be 80 cookies. So then you would round it to 32,000. You may be wondering why there are 0s and not the numbers? After you round the number you need to reset the numbers/value below it to 0.

Lyrx [107]3 years ago

3 0

Answer:

32000

Step-by-step explanation:

We need to add before we round

27,498 + 4,657

I like to line it up vertically

27,498

+ 4,657

-------------------

32,155

We are rounding to the nearest thousand

We are rounding the 2 so we look at the 1

1<5 so we will leave the 2 alone

32155 rounds to 32000

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According to the National Bridge Inspection Standard (NBIS), public bridges over 20 feet in length must be inspected and rated e

slamgirl [31]

Answer:

1.80% probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

Step-by-step explanation:

For each bridge, there are only two possible outcomes. Either it has rating of 4 or below, or it does not. The probability of a bridge being rated 4 or below is independent from other bridges. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

For the year 2020, the engineers forecast that 9% of all major Denver bridges will have ratings of 4 or below.

This means that $p = 0.09$

Use the forecast to find the probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

Either less than 4 have a rating of 4 or below, or at least 4 does. The sum of the probabilities of these events is 1.

$P(X < 4) + P(X \geq 4) = 1$